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olasank [31]
3 years ago
14

Does this look right?

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

yeah

Step-by-step explanation:

its basically looks good, if your teacher gives a bad grade than idk, but looks about right :)

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Identify the expression which represents the calculation “subtract 3 from 15, then divided by 6
matrenka [14]

Answer:

\frac{15-3}{6}

Step-by-step explanation:

You would start by writing the expression for “subtract 3 from 15", which would be \frac{15-3}{6}, then you would add on "then divided by 6", which would make it

4 0
2 years ago
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What are the following values from least to greatest 0 6 1/2 -1 9 can you help me pleaseeee​
alisha [4.7K]
-1, 0, 1/2, 6, 9 hope that helps
7 0
2 years ago
Nonsense will be reported!!​
Contact [7]

Answer:

See below

Step-by-step explanation:

d = 78° (Vertical angles)

h = 70° (Vertical angles)

Measure of angles d and h are are not equal. therefore they are not congruent.

7 0
2 years ago
How many subsets of {1, 2, 3, 4, 6, 8, 10, 15} are there for which the sum of the elements is 15?
stepladder [879]

Answer:

512

Step-by-step explanation:

Suppose we ask how many subsets of {1,2,3,4,5} add up to a number ≥8. The crucial idea is that we partition the set into two parts; these two parts are called complements of each other. Obviously, the sum of the two parts must add up to 15. Exactly one of those parts is therefore ≥8. There must be at least one such part, because of the pigeonhole principle (specifically, two 7's are sufficient only to add up to 14). And if one part has sum ≥8, the other part—its complement—must have sum ≤15−8=7

.

For instance, if I divide the set into parts {1,2,4}

and {3,5}, the first part adds up to 7, and its complement adds up to 8

.

Once one makes that observation, the rest of the proof is straightforward. There are 25=32

different subsets of this set (including itself and the empty set). For each one, either its sum, or its complement's sum (but not both), must be ≥8. Since exactly half of the subsets have sum ≥8, the number of such subsets is 32/2, or 16.

8 0
3 years ago
HELP PLeaseeeee!!!!!!!
hram777 [196]
The correct answer is C.

4 0
3 years ago
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