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3 years ago

PLEASE HURRY

2 answers:

7 0

<h2>Replacement costs for all contents in your home, including high cost electronics. In my case it was C on edge</h2><h2></h2>

Gekata [30.6K]3 years ago

6 0

Answer:

Step-by-step explanation:

Replacement costs for all contents in your home, including high cost electronics.

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Purchased a book rs 500 sold 20%profit find its actual profit and sel<br>ling price

umka2103 [35]

Answer:

Selling price=rs.600.

Profit of rs=100.

Step-by-step explanation:

C.P=500; profit%=20%

S.P.=100+profit%×C.P/100

S.P=120×500/100

=rs.600

S.P>C.P

Profit S.P-C.P

600-500=100

he gained for rs.100.

7 0

2 years ago

Given f(x)=8x+13 and g(x)=x^2-5x, find (f-g)x

uysha [10]

(f-g)x= -x²+13x+13

Hope it helps you....

4 0

3 years ago

Find the length of QP given Q is the midpoint of XF, PQ =2X+1, XF=7X-4, PF=X

nadezda [96]

Answer:

Therefore the length of QP = 3.4 units

Step-by-step explanation:

Given:

PQ = 2x + 1

XF = 7x - 4

PF = x

Q is the mid poimt of XF

∴ XQ = QF

QF = PQ - PF ..........( Q - F - P )

= 2x + 1 - x

∴ QF = x + 1

∴ XQ = QF = x + 1

TO Find:

QP = ?

Solution:

By Addition Property we have

$XP = XQ + QF+PF ..........(X-Q-F-P)\\\\$

$XF + PF =XQ + QF+PF ..........(X-Q-F-P)\\$

Substituting the given values in above equation we get

(7x - 4) + x = (x +1) + (x +1) + x

8x -4 = 3x +2

8x - 3x + 4 + 2

5x = 6

∴ $x = \frac{6}{5}$

Now we require

QP = (2x + 1)

∴ $QP = 2\times \frac{6}{5} +1\\\\QP = \frac{12+5}{5} \\\\QP =\frac{17}{5} \\\\\therefore QP = 3.4\ unit$

Therefore the length of QP = 3.4 units

3 0

2 years ago

What is the average rate of change of the function from X=2 to x=4

RideAnS [48]

Answer:

I have no results if I get some I will notify you

Step-by-step explanation:

I hope that help's

4 0

2 years ago

How long would it take to double your principal in an account that pays 6.5% annual interest compounded continuously? round your

prisoha [69]

It would take 10.7 years.

The formula for continuously compounded interest is:
$A=Pe^{rt}$
where P is the principal, r is the interest rate as a decimal number, and t is the number of years.

Using our information we have:
$A=Pe^{0.065t}$

We want to know when it will double the principal; therefore we substitute 2P for A and solve for t:
$2P=Pe^{0.065t}$

Divide both sides by P:
$\frac{2P}{P}=\frac{Pe^{0.065t}}{P}
\\
\\2=e^{0.065t}$

Take the natural log, ln, of each side to "undo" e:
$\ln{2}=\ln{e^{0.065t}}
\\
\\0.6931471806=0.065t$

Divide both sides by 0.065:
$\frac{0.6931471806}{0.065}=\frac{0.065t}{0.065}
\\
\\10.7\approx t$

8 0

3 years ago

Read 2 more answers