Answer:
Selling price=rs.600.
Profit of rs=100.
Step-by-step explanation:
C.P=500; profit%=20%
S.P.=100+profit%×C.P/100
S.P=120×500/100
=rs.600
S.P>C.P
Profit S.P-C.P
600-500=100
he gained for rs.100.
Answer:
Therefore the length of QP = 3.4 units
Step-by-step explanation:
Given:
PQ = 2x + 1
XF = 7x - 4
PF = x
Q is the mid poimt of XF
∴ XQ = QF
QF = PQ - PF ..........( Q - F - P )
= 2x + 1 - x
∴ QF = x + 1
∴ XQ = QF = x + 1
TO Find:
QP = ?
Solution:
By Addition Property we have


Substituting the given values in above equation we get
(7x - 4) + x = (x +1) + (x +1) + x
8x -4 = 3x +2
8x - 3x + 4 + 2
5x = 6
∴ 
Now we require
QP = (2x + 1)
∴ 
Therefore the length of QP = 3.4 units
Answer:
I have no results if I get some I will notify you
Step-by-step explanation:
I hope that help's
It would take 10.7 years.
The formula for continuously compounded interest is:

where P is the principal, r is the interest rate as a decimal number, and t is the number of years.
Using our information we have:

We want to know when it will double the principal; therefore we substitute 2P for A and solve for t:

Divide both sides by P:

Take the natural log, ln, of each side to "undo" e:

Divide both sides by 0.065: