Answer:
This equation does have real solutions contrary to your question. They are 
OR 
.
Step-by-step explanation:
In order to prove this has real number solutions, we simply need to use the quadratic formula. To do this, we first need to solve for 0.
2x^2 + 18x = 10
2x^2 + 18x - 10 = 0
Now that we have this and they are all factors of 2, we can divide everything by 2 for ease.
2x^2 + 18x - 10 = 0
x^2 + 9x - 5 = 0
Now we can use the quadratic equation to solve. Remember that A = 1 due to the coefficient of x^2, B = 9 as the coefficient of x and C = -5 as the constant.
OR
First do inside the parenthesis first.
When dividing two exponents subtract them.
15-5 = 10
So w^15 / w^5 becomes w^10
Now you have (w^10)^4
Now multiply the exponents:
10 x 4 = 40
Final answer is w^40
Answer:- D shows the triangle pairs which can be mapped to each other using a single translation.
Explanation:-
Translation is a rigid transformation which creates a congruent image as that of the original figure such that the distance between the each point of the original figure and the image is fixed and same.
The translation mapping is given by (x,y)→(x+h,y+k) ,where h is the distance of the x coordinate of the each point of the original figure to the image and k is the distance of the y coordinate of the each point of the original figure to the image.
In figure D we can see that the distance between each point of ΔCED is equal to the distance between each point of ΔMPN. Thus it shows the triangle pairs which can be mapped to each other using a single translation.
L=2W+3, A=LW, using L from the first in the second gives you:
A=(2W+3)W
A=2W^2+3W, and we are told A=90 so
2W^2+3W=90
2W^2+3W-90=0
2W^2-12W+15W-90=0
2W(W-6)+15(W-6)=0
(2W+15)(W-6)=0, since W>0 for all real possibilities,
W=6ft, and since L=2W+3
L=15ft
So the pool will be 6 ft wide by 15 ft long.
