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kolezko [41]
4 years ago
12

in a rock concert ,2/7 of spectators purchased 1000rs tickets while remaining 15000 purchased 500rs tickets. how many spectators

viewed the concert
Mathematics
2 answers:
sweet-ann [11.9K]4 years ago
8 0
[tex]15000= \frac{5}{7}*x[\tex]
[tex]x=15000* \frac{7}{5}=21,000[\tex] 

Check 21,000 * 2/7 = 6.000 and 6,000 + 15,000 = 21,000
forsale [732]4 years ago
4 0
2/7 purchased 1000...therefore, 5/7 purchases 500...and 5/7 is 15000 people.
so 5/7 of what = 15000
5/7x = 15000
x = 15000 * 7/5
x = 105000/5
x = 21000 people viewed the concert
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topjm [15]

Answer:  B. neither

<u>Step-by-step explanation:</u>

A function is even when f(x) = f(-x).

A function is odd when f(-x) = -f(x).


f(x) = 2x³ - x²

f(-x) = 2(-x)³ - (-x)²

      = -2x³ - x²

f(x) = 2x³ - x²     ≠    f(-x) = -2x³ - x²     so it is NOT EVEN


-f(x) = -(2x³ - x²)

      = -2x³ + x²

f(-x) = -2x³ - x²     ≠    -f(x)= -2x³ + x²     so it is NOT ODD  


Therefore, it is NEITHER even nor odd.

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3 years ago
Angle mIJK=180, angle mIJU = 3x-7, and angle mUJK=17x + 7 find angle mIJU
Andrej [43]

Answer:

The measure of angle IJU is 20 degrees.

Step-by-step explanation:

In order to find that, we need to add the two angles together and set equal to 180 degrees. Then we can solve for x.

(3x - 7) + (17x + 7) = 180 ----> Combine like terms

20x = 180 -----> Divide by 20

x = 9

Now that we have this, we can stick the value into the equation and solve for IJU.

IJU = 3x - 7

IJU = 3(9) - 7

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ArbitrLikvidat [17]

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The graph of g(x) is shifted 4 units down.

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Plz help<br>urgent !!!!<br>will give the brainliest !!​
Mkey [24]

Answer:

X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}

Step-by-step explanation:

The question we have at hand is, in other words,

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix} - where we have to solve for the value of X

If we have to isolate X here, then we would have to take the inverse of the following matrix ...

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix} ... so that it should be as follows ... \begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}

Therefore, we can conclude that the equation as to solve for " X " will be the following,

X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} - First find the 2 x 2 matrix inverse of the first portion,

\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1} = \frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}= \frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix} = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} ,

X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix} - Simplifying this, we should get ...

\begin{bmatrix}1&3\\ 2&4\end{bmatrix} ... which is our solution.

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