Question

Angle(<)K and <L are complementary angles. If m<K = 3x+3 and m<L = 10x-4, find the measures of both angles.

Answer 1

3x+3 + 10x-4 +90 (because complementary angle add up to 90)

13x-1+90 (add 1)

13x/13=91 (divide 13 on both sides)

x=7

now you fill in 7 for x

m<K=24 and m<L=66

hope i helped

Answer 2

Answer:

m∠K is 24° and m∠L is 66°

Step-by-step explanation:

Since, two angles are complementary if their sum is equal to 90°,

Given,

m∠K = 3x + 3

m∠L = 10x - 4

∵ ∠K and ∠L are complementary angles,

So, by the above statement,

$m\angle K+m\angle L = 90^{\circ}$

$3x+3+10x-4=90$

$13x-1=90$

$13x=91$

$\implies x=7$

Hence, the measures of angle K = 3(7) + 3 = 21 + 3 = 24°,

And, the measures of angle L = 10(7) - 4 = 70 - 4 = 66°