All categories

2 years ago

PLEASE ANSWER!!! First answer gets brainliest!!!!! RIGHT ANSWERS ONLY!

Mathematics

1 answer:

hammer [34]2 years ago

6 0

AD = √(AB^2+BC^2+CD^2)

AD = √(12^2+9^2+10^2)

AD = √(144+81+100)

AD = √325

AD = 18.02 = 18

ANSWER:

F. 18 feet

You might be interested in

In this figure a || b Find the measure of each angle using either of the given angle measures. Identify the reason for each answ

geniusboy [140]

Answer:

$m$

Step-by-step explanation:

Part 1) Find the measure of angle 1

we know that

$m$ -----> by supplementary angles

$m$

Part 2) Find the measure of angle 2

we know that

$m$ -----> by alternate exterior angles

Part 3) Find the measure of angle 3

we know that

$m$ -----> by vertical angles

Part 4) Find the measure of angle 4

we know that

$m$ ------> by corresponding angles

Part 5) Find the measure of angle 5

we know that

$m$ -----> by vertical angles

$m$

Part 6) Find the measure of angle 6

we know that

$m$ -----> by supplementary angles

we have

$m$

substitute

$86\°+m$

$m$

3 0

2 years ago

Which equation represents a proportional relationship? A y=x+13y=x+\frac{1}{3}y=x+ 3 1 B y=1−13xy=1-\frac{1}{3}xy=1− 3 1 x C

yanalaym [24]

Answer:

fkgjhkghejejkekegejehe

7 0

2 years ago

Help me please asap im begging

Mila [183]

Answer: 4

Step-by-step explanation: :)

5 0

1 year ago

PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!

jonny [76]

Answer:

Here we will use the relationships:

$a^n*a^m = a^{n + m}$

$(a^n)^m = a^{n*m}$

$\frac{a^n}{a^m} = a^{n - m}$

And a number:

$a^n$

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) $5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}$

This is between zero and 1,

B) $\frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}$

This is greater than 1, because the exponent is positive.

C) $(\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5$

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) $\frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}$

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

So (-7)^-2 = 7^-2

4 0

2 years ago

Which of the following relations is a function?

Murljashka [212]

Answer:

c is the one with function

3 0

2 years ago