Show that (a-b)/(√a-√b)=√a+√b for all values of a and b such that a> 0 and b> 0 and a≠b.
2 answers:
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Let's see what to do...
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Step (1)
Look : 16 , 10 , 4 , ...
It is an arithmetic sequence.
So first we have to find the value of the ratio(( d )) .
To do this, we need to subtract each sentence minus the previous sentence.
So we have : 10 - 16 = - 6
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Step (2)
To find the nth sentence in an arithmetic sequence, we must use the following equation :
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Step (3)
To find the 6th term just need to put the following parameters in the above sequence.
t(1) = 16 ------ n = 6 ------ d = -6
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And we're done.
Thanks for watching buddy good luck.
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