Question

Show that (a-b)/(√a-√b)=√a+√b for all values of a and b such that a> 0 and b> 0 and a≠b.

Answer 1

Answer:=a-b

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

$\frac{a-b}{\sqrt{a} -\sqrt{b}} =\sqrt{a} +\sqrt{b}\\or ~a-b=(\sqrt{a} +\sqrt{b})(\sqrt{a} -\sqrt{b} )=(\sqrt{a} )^2-(\sqrt{b} )^2 =a-b$