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3 years ago

7

15=3y+7.y= please help me with my assignment i havelike 57 more questions to answer and 10% im trying by myself to solve the res

t are kinda difficult

1 answer:

monitta3 years ago

7 0

Answer:

8/3 or 2.67 to nearest hundredth.

Step-by-step explanation:

15 = 3y + 7

15 - 7 = 3y

3y = 8

y = 8/3

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The formula can be used to work outthe cost, in riyals, of hiring a helmet inQatar for a number of days.Kasun wants to hire a bi

Margaret [11]

Answer:

The answer is below

Step-by-step explanation:

a) Cost of hiring the bicycle for 14 days is:

Cost = 65 * 14 days + 44 = 954 riyals

b) The number of days the bicycle is hired is to be the same as the number of days the bicycle is to be hired. Let us assume that the bicycle and helmet is to be hired for x days, hence:

Cost of bicycle = 65 * x + 14 = 65x + 44

Cost of helmet = 12.5 * x = 12.5x

Total cost = 65x + 44 + 12.5x = 77.5x + 44

Since 750 riyals is available, hence:

750 = 77.5x + 44

77.5x = 706

x = 9.11

Therefore the maximum number of days is 11. The total cost for 11 days is:

Total cost = 77.5(9) + 44 = 741.5 riyals

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6 0

2 years ago

What symbol makes the comparison true

olga_2 [115]

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3 0

2 years ago

What is the length of CD ? In this diagram ABC EDC ?<br> Please help !!!!

n200080 [17]

Answer:
CD = x = 4 units

Explanation:
We are given that the two triangles are similar. This means that we can set the similarity proportionality as follows:
$\frac{BC}{CD} = \frac{CA}{CE} = \frac{AB}{ED}$

W e have:
BC = 20 - x
AC = 20
CD = x
CE = 5

Substitute in the above proportionality and solve for x as follows:
$\frac{20-x}{x} = \frac{20}{5} = 4$

4x = 20 - x
5x = 20
x = 4

Based on he above:
CD = 4 units
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Hope this helps :)

5 0

3 years ago

Read 2 more answers

The focus of a parabola is located at (0,–2). The directrix of the parabola is represented by y = 2. Which equation represents t

Archy [21]

Answer:

$\boxed{x^2=-8y}$

Step-by-step explanation:

$(a,b)\ is \ the\ focus\\y=k\ is \ the\ directrice\\\\Formula\ to\ use:\ y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\Here: \ a=0,\ b=-2, \ k=2\\\\y=\dfrac{(x-0)^2}{2(-2-2)} +\dfrac{-2+2}{2} \\\\so\ y=-\dfrac{x^2}{8} \\\\or\ x^2=-8y$

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2 years ago

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dem82 [27]

Answer:

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2 years ago