Answer:
y2 = m(x2-x1)+y1
Step-by-step explanation:
Given the expression;
m = y2-y1/x2-x1
Making y2 the subject of the formula
Cross multiply
m(x2-x1) = y2-y1
Add y1 to both sides
m(x2-x1)+y1 = y2-y1+y1
m(x2-x1)+y1 = y2
Hence y2 = m(x2-x1)+y1
Answer:
there is hint for u in the book darling
you can refer example 4 in the same book
Answer:
p = -4
Step-by-step explanation:
So first of all, you need to combine like terms. In order for that to happen, you need the like terms on one side. You get rid of a number by adding ( if subtraction), multiplying (if division), and subtracting (if addition) by its reciprical. Since it is a negative 3, you add it. Whatever you do to one side, you have to do to the other. That leaves us to 4p = 9 + 7p +3 or 4p = 12 + 7p. Since 7p is positive, you have to subtract from both side leaving us with 4p - 7p = 12 or -3p = 12. You then divide both sides with -3 to isolate the variable leaving us with p = -4
Answer:
Congrats!!!
Step-by-step explanation:
FINALLY......
Just kidding...im just here to waste your time
