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Rus_ich [418]
3 years ago
11

At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad

ow be if they are 4 feet tall?
Please help ASAP!!! :(
Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0

<u>Answer:</u>

The length of the person’s shadow is 5.7ft

<u>Explanation:</u>

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the  rules of trigonometry

\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}

\frac{a}{b}=\frac{c}{d}

\frac{35}{50}=\frac{4}{d}

35d=200

d=\frac{200}{35}

d=5.7ft  

Hence, The length of the person’s shadow is 5.7ft.

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Solve the equation 2^(2x+1)+8=17×2^x.
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Oooh, looks fun

ok
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we might want to know some properties
(x^m)(x^n)=x^{m+n}
(a^b)^c=a^{bc}
if a^m=a^n where a=a, then assume m=n

2^{2x+1}=(2^{2x})(2^1)
so
(2^{2x})(2)+8=17(2^x)
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(2^x)^2(2)+2^3-17(2^x)=0
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ac method
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2^3=2^x
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and
\frac{1}{2}=2^x
2^{-1}=2^x
-1=x

x=-1 and 3
neat problem
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