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zzz [600]
3 years ago
6

PLZ HELPPP OMG I WILL GIVE 50 POINTS NOT A SCAM I HAVE A QUIZ GRADE DEPENDS ON THIS

Mathematics
1 answer:
nekit [7.7K]3 years ago
5 0

Answer:


Step-by-step explanation:

All I know is x is 20 and y is $48.75 sorry.

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7×9-8+11-6 [5+2 (-3)]
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Ok, MissWalker! Please try your best to understand this, it may get confusing.
I have solved this on a different website, and here is my solving in a picture. I hope I helped!!! :D

8 0
3 years ago
Linda collects a random sample of 12 of the 98 Wilderness Club members’ ages. She makes an inference that most wilderness club m
mash [69]
The box plot that would confirm the inference that Linda made would have a minimum value of 20 and a maximum value of 40. Somewhere in the between is the mean. The box plot should have a confidence interval of 95% in order to have the inference valid.<span />
7 0
2 years ago
£12000 in savings<br> 1.5% interest per year<br> Value after 2 years
kari74 [83]

Answer:treeeeeeeeeeeeeeeeeeeeeeee

reuwq9iasuoajkaseeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:eeeeeeeeeeeeeeeeeeeeeeeeee

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7 0
2 years ago
Answer while showing work I need u to show ur work and answer
skad [1K]

Answer:

7cm

Step-by-step explanation:

One side of a square is increased by 8 cm, let us say the length got increased by 8 cm. So we have length of x + 8 cm

An adjacent side, the width, decreased by 2 cm. So we have width of x - 2cm

Perimeter of rectangle = 2(length + width)

40 = 2( (x + 8) + ( x - 2) )

40 = 2( 2x + 6)

40 = 4x + 12

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That is 7 cm of the length of the side of the square

4 0
3 years ago
Please help with imaginary numbers worksheet!
mihalych1998 [28]

Problem 5

<h3>Answer:   6i</h3>

------------------

Explanation:

We have these four identities

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = -i

Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.

We can think of it like this if you wanted

i^28 = (i^4)^7 = 1^7 = 1

Then the sqrt(-36) becomes 6i

So overall, we end up with the final answer of 6i

=============================================

Problem 6

<h3>Answer:  -3i</h3>

------------------

Explanation:

We'll use the ideas mentioned in problem 5

46/4 = 11 remainder 2

i^46 = i^2 = -1

sqrt(-9) = 3i

The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i

In other words, here is one way you could write out the steps

-i^{46}*-\sqrt{-9}\\\\-i^{2}*-3i\\\\i^{2}*3i\\\\-1*3i\\\\-3i\\\\

=============================================

Problem 7

<h3>Answer:   -1</h3>

------------------

Work Shown:

i^10 = i^2 because 10/4 = 2 remainder 2

i^19 = i^3 because 19/4 = 4 remainder 3

i^7 = i^3 because 7/4 = 1 remainder 3

Again, all we care about are the remainders.

i^{10}+i^{19} - i^{7}\\\\i^{2}+i^{3} - i^{3}\\\\i^{2}\\\\-1

=============================================

Problem 8

<h3>Answer:    -1 + i</h3>

------------------

Work Shown:

i^22*i^6 = i^(22+6) = i^28

Earlier in problem 5, we found that i^28 = i^0 = 1

So,

i^1 - \left(i^{22}*i^{6}\right)\\\\i^1 - i^{28}\\\\i^1 - i^{0}\\\\i - 1\\\\-1+i

8 0
2 years ago
Read 2 more answers
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