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Oksana_A [137]
2 years ago
15

A family of 6 is going to the fair. They have a coupon for $2.50 off each ticket. If they pay $96 for all their tickets, and eac

h ticket costs the same amount, how much does a ticket, t, cost without the coupon?
Mathematics
2 answers:
vredina [299]2 years ago
7 0

Answer:

6x=46.50

Step-by-step explanation:

Kobotan [32]2 years ago
3 0

Answer:

6x=46.50

Step-by-step explanation:

You might be interested in
the perimeter of the rectangle below is 98 units. Find the length of CD. Write your answer without variables. cd=4x+3 cb=5x+1
zimovet [89]

2(4x + 3) + 2(5x + 1) = 98 \\ 8x + 6 + 10x + 2 = 98 \\ 18x + 8 = 98 \\ 18x = 90 \\  x = 5
Substitute x with 5,

CD =
4x + 3 \\  = 4(5) + 3 \\  = 20 + 3 \\  = 23
CD = 23 units

Hope this helps.
7 0
3 years ago
Read 2 more answers
How is this solved using trig identities (sum/difference)?
GenaCL600 [577]
FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

cos \beta = -\frac{1}{2}  \sqrt{3}

tan \beta= \frac{1}{3}  \sqrt{3}

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2}  \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )
sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )
sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )
cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )
cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )

Find tan (α - β)
tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha  tan \beta }
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}

Simplify the denominator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5\sqrt{3}}{24})}
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the numerator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }
tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the fraction
tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})
tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}

7 0
3 years ago
VG¯¯¯¯¯¯¯¯=12.2 in. PG¯¯¯¯¯¯¯¯=13.1 in. Find the radius of the circle.
LuckyWell [14K]

Answer:iiii

Step-by-step explanation:iiiii

4 0
3 years ago
Please helppp meee I need it done noww
bearhunter [10]

Answer:

7/2

Step-by-step explanation:

3 wholes is equal to 6 halves plus a half equals 7 halves

6 0
3 years ago
Have to show all work
Natasha2012 [34]

Answer:

4.58 ft

Step-by-step explanation:

Pythagoras Theorem:

a^2 +b^2 = c^2

b^2 = c^2 - a^

b^2 =11^2 - 10^2

b^2 = 121 - 100

b^2= 21

the heigh = √21 = 4.58

Answer: 4.58 ft

6 0
3 years ago
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