A]
D=R×t
d=5.8r
d2=5.1(r+7)
0.7r=35.7
r=51 mi/hr
thus the average speed on the outbound trip would be:
51+7=58 mi/hr
b]
let speed of fishing boat=x km/h
speed of cruise ship=(x+12.5) km/h
distance traveled by fishing boat=11.5×x=11.5x km
distance traveled by cruise ship=(x+12.5)×11=(11x+137.5) km
Total distance covered by the ships:
11.5x+11x+137.5=322
22.5x=322-137.5
22.5x=184.5
thus
x=184.5/22.5
x=8.2 km/h
The speed of fishing boat is 8.2 km/hr
1) y:10;
2) 4p+6q;
3) x +( x+ 1) = 59 => 2x = 58 => x = 29 => 29 and 30;
Answer:
D
Step-by-step explanation:
∠1 + ∠2 = 180 {Supplementary angles}
6x + 15 + 3x + 3 = 180
6x + 3x + 15 + 3 = 180
Combine like terms
9x + 18 = 180
Subtract 18 from both sides
9x = 180 - 18
9x = 162
x = 162/9
x = 18
∠2 = 3x +3
= 3*18 + 3
= 54 + 3
∠2 = 57°
Answer:
The answer to your question is Katie had 15 rocks and Oliver 45 rocks.
Step-by-step explanation:
Conditions
Katie has x amount of rocks
Oliver has 3x amount of rocks
The final amount of rocks
Oliver = 3x + 75
Katie = x + 105
Now, they have the same amount of rocks, then we can equal both equations
3x + 75 = x + 105
Solve for x
3x - x = 105 - 75
2x = 30
x = 30/2
x = 15
Conclusions
At first Katie had 15 rocks and Oliver had 3(15) = 45 rocks
Let x represent the # of people in sid’s group: 200 - (16.25x + 6.50x) = 18.25
200 - 22.75x = 18.25
-22.75x = -181.75
x = about 8
if Sid is not included in the group, i think the answer is D. 7, but im not sure
