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3 years ago

Help test due tonight! no links please

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

5 0

(7,-3)
(1,-3)
Have a great day

shusha [124]3 years ago

4 0

Answer:

The original point is (7,-3)

Final figure is (1,-3)

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Will give brainliest if done properly

k0ka [10]

Answer:

$\sf \boxed{ \sf y - 3 = \dfrac{3}{2} (x - 6)}$

Explanation:

$\sf Given \ equation: y = \dfrac{3}{2} x - 5$

Comparing it with slope intercept form "y = mx + b" where 'm' is slope and 'b' is y-intercept.

Here slope: 3/2 and y-intercept: -5

Parallel slope has the same tangent slope.

Pass through point (x, y) = (6, 3)

Equation:

$\sf y - y_1 = m(x - x_1)$

$\rightarrow \sf y - 3 = \dfrac{3}{2} (x - 6)$

6 0

2 years ago

What is 1 million times 4358

adelina 88 [10]

Answer:

What is 1 million times 4358

Step-by-step explanation:

You add 6 zeros on the end since million has 6 zeroes.

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3 years ago

Function 1 is defined by the equation y=2x+10

cricket20 [7]

Answer:

C. The functions have the same y-intercept

Step-by-step explanation:

In slope intercept form, y = mx + b, b represents the y-intercept, and in the first function the y-intercept is 10.

The y-intercept is when x = 0, and in the chart, when x equals 0, y equals 10.

10 = 10, so they have the same y-intercept.

5 0

3 years ago

PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198

Elena-2011 [213]

The weight in 1980 is $\frac{4k}{5}$ kilograms

Solution:

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

To find: weight in 1980

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

The percentage increase is given by formula:

$\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100$

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

Substituting the values in formula,

$25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}$

Thus the weight in kilograms in 1980 is $\frac{4k}{5}$

7 0

3 years ago

What is the coefficient of the term of degree 5 in the polynomial below? 3x6 + 5 - x2 + 4x5 - 9x A. 5 B. 4 C. 3 D. 6

liq [111]

4x^5 is a term of degree 5, and its coefficient is 4

6 0

3 years ago

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Help test due tonight! *no links please *

Help test due tonight! no links please