Question

Which quadratic function in standard form has the values a = –3.5, b = 2.7, and c = –8.2? f(x) = 2.7x2 – 8.2x – 3.5 f(x) = 2.7x2 – 3.5x – 8.2 f(x) = –3.5x2 – 8.2x + 2.7 f(x ) = –3.5x2 + 2.7x – 8.2

Answer 1

Answer:

Option (d) is correct.

The standard form is  $f(x)=-3.5x^2+2.7x-8,2$

Step-by-step explanation:

Given :  a = –3.5, b = 2.7, and c = –8.2

We have to write the quadratic function in standard form and choose from the given options.

The standard form of quadratic function is $f(x)=ax^2+bx+c$  , where a , b, ca re constants.

Given a = –3.5, b = 2.7, and c = –8.2

Substitute in the standard form , we get,

Thus, the standard form is  $f(x)=-3.5x^2+2.7x-8,2$

Thus, Option (d) is correct.

Answer 2

A is the coefficient of x^2, b is the coefficient of x and c is the constant term.
The correct answer is therefore:
$f(x)=-3.5x^{2}+2.7x-8.2.$