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harkovskaia [24]
3 years ago
15

If the probability that 42 or fewer kids in a group of 57 like pizza is 79%, what is the probability that at least 43 kids in th

e group like pizza?
Mathematics
2 answers:
weqwewe [10]3 years ago
7 0

Answer:

Step-by-step explanation:

43

Art [367]3 years ago
6 0

You’re answer in simple terms is 21

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Can someone put this in order
zaharov [31]
The first has value 2500*(1+.05*9)=3625.  The second, similarly, has value 4160, and the third, 3400.  Thus, the order, from least to greatest, is third, first, second.
3 0
3 years ago
Determine the x-intercept points of the function h(x) = (x - 5)(x-6)(x + 4).
AlexFokin [52]

Answer:

A.

Step-by-step explanation:

The x-intercepts are the points where the x value is zero. In this case, to find the "zeros" of the function, set each factor to zero. x-5 -> x=5. x-6 -> x=6. x+4 -> x=-4.

7 0
3 years ago
The graph below shows four sections: A, B, C, and D.
Gemiola [76]
It’s c
Hope this helps
4 0
3 years ago
Joyce old 218 cupcakes of lemonade at his lemonade stand. What is 218 rounded to the nearest tens
MAXImum [283]

220

from 218 the 1 is in the tens column. this is the figure that needs to be rounded.

using the following rule

If the digit after the 1 is ≥ 5 then round 1 up to 2

If the digit after the 1 is < 5 then the 1 remains as 1

here the digit after the 1 is 8 so the 1 in the ten's column becomes 2 and the 8 is replaced by 0

218 ≈ 220 ( to the nearest ten )


7 0
3 years ago
Find the area of the shaded region. Round your answer to the nearest tenth.
Alex
Check the picture below on the left-side.

we know the central angle of the "empty" area is 120°, however the legs coming from the center of the circle, namely the radius, are always 6, therefore the legs stemming from the 120° angle, are both 6, making that triangle an isosceles.

now, using the "inscribed angle" theorem, check the picture on the right-side, we know that the inscribed angle there, in red, is 30°, that means the intercepted arc is twice as much, thus 60°, and since arcs get their angle measurement from the central angle they're in, the central angle making up that arc is also 60°, as in the picture.

so, the shaded area is really just the area of that circle's "sector" with 60°, PLUS the area of the circle's "segment" with 120°.

\bf \textit{area of a sector of a circle}\\\\&#10;A_x=\cfrac{\theta \pi r^2}{360}\quad &#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;r=6\\&#10;\theta =60&#10;\end{cases}\implies A_x=\cfrac{60\cdot \pi \cdot 6^2}{360}\implies \boxed{A_x=6\pi} \\\\&#10;-------------------------------\\\\

\bf \textit{area of a segment of a circle}\\\\&#10;A_y=\cfrac{r^2}{2}\left[\cfrac{\pi \theta }{180}~-~sin(\theta )  \right]&#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;r=6\\&#10;\theta =120&#10;\end{cases}

\bf A_y=\cfrac{6^2}{2}\left[\cfrac{\pi\cdot 120 }{180}~-~sin(120^o )  \right]&#10;\\\\\\&#10;A_y=18\left[\cfrac{2\pi }{3}~-~\cfrac{\sqrt{3}}{2} \right]\implies \boxed{A_y=12\pi -9\sqrt{3}}\\\\&#10;-------------------------------\\\\&#10;\textit{shaded area}\qquad \stackrel{A_x}{6\pi }~~+~~\stackrel{A_y}{12\pi -9\sqrt{3}}\implies 18\pi -9\sqrt{3}

7 0
4 years ago
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