Don't open the link it's a scam
To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that

and the exponent

are divisible by index

. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is:
185-7=178
So 178÷185=0.9621621
0.96×100=96%
OR APPROXIMATELY 96 percent
Answer:
The 2nd y is 12, the 3rd y is 24 and the last x is 3
Step-by-step explanation:
1 quarter = 25 cents (he has 2 therefore its 50 cents)
10 dimes = 100 cents = 1 dollar
Oliver has twice as many dimes than he does quarters because 100 divided by 50 = 2. Hope this helps!