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2 years ago

Find the product. 5x2.2y2

Mathematics

1 answer:

ozzi2 years ago

3 0

Answer:10x^2y^2

Step-by-step explanation:

5x2 X 2y2=10x^2y^2

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A cube with edges of length x centimeters has volume v(x)=x^3 at the instant when x=2, what is the rate of change of x, in centi

Margarita [4]

Dv/dt=40 dv/dt=3x^2dx/dt
40=3x^2dx/dt
40=12dx/dt
10/3=dx/dt

5 0

2 years ago

Read 2 more answers

What's the equation for q and r

elena-14-01-66 [18.8K]

5 + 5 = 10
10 + 5 = 15
20 + 5 = 25
40 + 5 = 45

q + 5 = r

8 0

3 years ago

Assume that the car lot contains 40 percent BMWs, 25 percent Volvos, and 35 percent Jaguars. Of the BMWs, 90 percent have naviga

sveticcg [70]

Answer:

The required probability is 0.4098.

Step-by-step explanation:

Consider the provided information.

According to conditional probability that A occurs , given B has occurred.

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Assume that the car lot contains 40 percent BMWs, 25 percent Volvos, and 35 percent Jaguars.

Pr(BMWs)=0.40

Pr(Volvos)=0.25

Pr(Jaguars)=0.35

Of the BMWs, 90 percent have navigation systems, 30 percent of the Volvos have navigation systems, and 50 percent of the Jaguars have navigation systems.

Pr(Navigation | BMWs)=0. 90

Pr(Navigation l Volvos)=0.30

Pr(Navigation l Jaguars)=0.50

Total cars with navigation system = 0.40×0.90+0.25×0.30+0.35×0.50

=0.36+0.075+0.175=0.61

Pr(Not Bmw l Navigation system) = $\frac{0.25\times0.30+0.35\times0.50}{0.61}\approx0.4098$

Hence, the required probability is 0.4098.

6 0

3 years ago

What is <br> r squared+7r+6=0

Firlakuza [10]

Answer:

r = -6, -1

Step-by-step explanation:

r^2 + 7r+6 =0

Factor

What 2 numbers multiply to 6 and add to 7

6*1 =6

6+1 =7

(r+6) (r+1) =0

Using the zero product property

r+6 =0 r+1 =0

r = -6 r=-1

7 0

3 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.3 in, and a standard deviation given by

Salsk061 [2.6K]

Answer: a) 0.6141

b) 0.9772

Step-by-step explanation:

Given : Mean : $\mu= 62.3\text{ in}$

Standard deviation : $\sigma = \text{2.4 in}$

The formula for z -score :

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

a) Sample size = 1

For x= 63 in. ,

$z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{1}}}=0.29$

The p-value = $P(z$

$0.6140918\approx0.6141$

Thus, the probability is approximately = 0.6141

b) Sample size = 47

For x= 63 ,

$z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{47}}}\approx2.0$

The p-value = $P(z$

$=0.9772498\approx0.9772$

Thus , the probability that they have a mean height less than 63 in =0.9772.

8 0

3 years ago