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Naya [18.7K]
3 years ago
14

Compare the graphs of the functions listed below. Function 1: y = 0.25x2 Function 2: y = 4x2 Function 3: y = -½x2 Function 4: y

= -16x2 The graph of is the widest.
Mathematics
2 answers:
V125BC [204]3 years ago
3 0
The graph of y = 0.25x2<span> is the widest.</span>
Maru [420]3 years ago
3 0

Answer:

A. Function 1

B. Function 4

C. Narrower than

Step-by-step explanation:

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Question 32 of 40<br> The ratio<br> opposite<br> hypotenuse<br> describes which function?
Helen [10]

The ratio \frac{Opposite}{Hypotenuse } describes the Sine function . The correct option is C. Sine

<h3>Trigonometry </h3>

From the question, we are to determine the function that the ratio of <em>opposite </em>to <em>hypotenuse </em>describes

By SOH CAH TOA

We have that

Sine = \frac{Opposite}{Hypotenuse }

Cosine = \frac{Adjacent}{Hypotenuse }

and

Tangent = \frac{Opposite}{Adjacent}

Hence, the ratio \frac{Opposite}{Hypotenuse } describes the Sine function . The correct option is C. Sine

Learn more on Trigonometry here: brainly.com/question/956353

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5 0
2 years ago
In the above figure, find the measure of angle AEB + the measure of angle CED.
matrenka [14]
Well, AEB is 28, and CED is 65,and you want  to add them, so that would be 65+28, which equals 80+13=93, so the answer is b.
8 0
3 years ago
I need help on this- nothing is right for me
tresset_1 [31]

Answer:

5. Area = 28.5 cm; 6. Area = 544,500 cm

Step-by-step explanation:

Area = Length×Width

5. You have to convert the mm to cm by dividing the mm by 10. Then just multiply the length and width.

6. Same thing; different unit, convert the m to cm (or vice versa, not sure which unit you need to answer in) and multiply the length and width.

7 0
2 years ago
Read 2 more answers
Cookies cost $3 each, and candies cost $2 each. Tim has
riadik2000 [5.3K]

Answer:

he can buy 5 cookies and 5 candies

Step-by-step explanation:

3+2=5

5×5=25

6 0
3 years ago
Read 2 more answers
A nationwide study of American homeowners revealed that 65% have one or more lawn mowers. A lawnequipment manufacturer, located
GenaCL600 [577]

Answer:

z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589  

p_v =P(z>1.589)=0.056  

If we compare the p value obtained with the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

Step-by-step explanation:

Data given and notation

n=497 represent the random sample taken

X=340 represent the homes in Omaha with one or more lawn mowers

\hat p=\frac{340}{497}=0.684 estimated proportion of homes in Omaha with one or more lawn mowers

p_o=0.65 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the true proportion of homes in Omaha with one or more lawn mowers is higher than 0.65.:  

Null hypothesis:p\leq 0.65  

Alternative hypothesis:p > 0.65  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>1.589)=0.056  

If we compare the p value obtained with the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

7 0
3 years ago
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