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3 years ago

14

Compare the graphs of the functions listed below. Function 1: y = 0.25x2 Function 2: y = 4x2 Function 3: y = -½x2 Function 4: y

= -16x2 The graph of is the widest.

2 answers:

V125BC [204]3 years ago

3 0

The graph of y = 0.25x2<span> is the widest.</span>

Maru [420]3 years ago

3 0

Answer:

A. Function 1

B. Function 4

C. Narrower than

Step-by-step explanation:

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What is the quotient (125 – 8x3) ÷ (25 + 10x + 4x2)? –2x + 5 2x – 5 –2x – 5 2x + 5

juin [17]

ANSWER

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = - 2x+5$

EXPLANATION

We have been given the quotient,

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} }$
to simplify.

We need to rewrite the numerator as difference of two cubes.

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ {5}^{3} - ( {2x})^{3} }{ 25 + 10x + 4 {x}^{2} }$

We need to make use of the difference of cubes formula,

${a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )$

We now let,
$a = 5 \: and \: b = 2x$

Then the numerator becomes,

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)(25 + 5 (2x) + {(2x)}^{2}) }{ 25 + 10x + 4 {x}^{2} }$

This simplifies to,

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)(25 + 10x + 4 {x}^{2}) }{ 25 + 10x + 4 {x}^{2} }$

We cancel out common factors to obtain,

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)}{ 1}$

$\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = 5 - 2x$

8 0

3 years ago

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Someone please help me with this

Alisiya [41]

Answer:

option 1 33 + 15x

Step-by-step explanation:

multiply by 3 throughout

so,

3 times 11 plus 3 times 5x so it's 33+15x, option 1

7 0

3 years ago

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I'm confused how do I simplify that??

Nina [5.8K]

2+3/5x-1-1/4x
2+3x-1/5-1-x/5
2+3/5x-1-x/5
1+3/5x-x/5
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8 0

3 years ago

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What’s the correct answer

tatyana61 [14]

21.3 is the correct answer.

7 0

3 years ago

The radius of a circle is 19 cm. Find its area in terms of pi

yan [13]

Answer:

38π cm

Step-by-step explanation:

The area of a circle of radius r is A = 2πr.

If the radius is 19 cm, then the area is A = 2π(19 cm), or 38π cm.

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3 years ago