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soldier1979 [14.2K]
3 years ago
5

Calculate the angle to the nearest degree: csc (x) = 1.0353

Mathematics
1 answer:
sammy [17]3 years ago
5 0

Answer:

75^{\circ}

Step-by-step explanation:

Given: \csc (x) = 1.0353

To find: angle to the nearest degree

Solution:

A triangle is a polygon that has three sides, three angles ,and three vertices.

Trigonometry explains the relationship between the sides and angles of the triangle.

The angle can be expressed in two forms: degrees or radians.

\csc (x) = 1.0353\\x=74.995\approx 75^{\circ}

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stellarik [79]
\frac{3}{7}w-11=\frac{4}{7}w\ \ \ \ \ \ \ |\cdot7\\\\3w-77=4w\\\\-77=4w-3w\\\\w=-77\\\\Answer\ is\ -77.
7 0
4 years ago
Someone plz help meh
gogolik [260]

Answer:

<em>f( g ( - 2 ) ) = - 14 </em>

Step-by-step explanation:

f(x) = - 2x + 4

g(x) = 3x² - x - 5

f( g ( - 2 ) ) = ?

g( - 2 ) = 3( - 2 )² - ( - 2 ) - 5 = 12 + 2 - 5 = 9

f(9) = - 2 × 9 + 4 = - 14

<em>f( g ( - 2 ) ) = - 14</em>

7 0
2 years ago
Can someone explain the steps for how do solve this?! I can’t get it right
Ulleksa [173]

Answer:

x = 50

m∠D = 150°

m∠F = 30°

Step-by-step explanation:

  • supplementary angles are two angles whose sum is 180°

∠D + ∠F = 180°

3x + x - 20 = 180

3x + x = 180 + 20

4x = 200

x = 200/4

x = 50

D = 3*50 = 150

∠D = 150°

F = 50 - 20 = 30

∠F = 30°

6 0
3 years ago
There are 16 pieces of fruit in a basket, including 2 nectarines. What is the probability that a randomly selected piece of frui
Ahat [919]

Answer:

1/8

Step-by-step explanation:

P(nectarine) = number of nectarines / total

                       =2/16

                        = 1/8

4 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
4 years ago
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