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Naddik [55]
2 years ago
6

Which product is represented by the hundredths grid A. 0.5 X 0.02 = 0.01

Mathematics
1 answer:
katrin [286]2 years ago
5 0

Answer:

The product of A would be the answer

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He should change the coefficient 5
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3 years ago
Chose all the values of x that are not in the domain of this rational function. Picture attached, 15 points and I'll give Brainl
pogonyaev

Answer:

All of them.

Step-by-step explanation:

For rational functions, the domain is all real numbers <em>except</em> for the zeros of the denominator.

Therefore, to find the x-values that are not in the domain, we need to solve for the zeros of the denominator. Therefore, set the denominator to zero:

x(x-1)(x^2-4)=0

Zero Product Property:

x\neq 0\text{ or }x-1\neq 0\text{ or }x^2-4\neq 0

Solve for the x in each of the three equations. The first one is already solved. Thus:

x-1\neq 0 \text{ or }x^2-4\neq 0\\x\neq 1\text{ or }x^2\neq 4\\x\neq 1 \text{ or }x\neq\pm 2

Thus, the values that <em>cannot</em> be in the domain of the rational function is:

x=-2,0,1,2

Click all the options.

6 0
3 years ago
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Stacy is saving $5 each week to buy a new bike. She already has 15 dollars saved in her bank account. SHe needs to save at least
kotykmax [81]

She nee to save $60 more so she can buy a new bike

3 0
2 years ago
I need help with this 20 points
iren2701 [21]

Answer:

I dont understand that sorry

4 0
3 years ago
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Triangle DEF has vertices D(−4, 1), E(2, 3), and F(2, 1) and is dilated by a factor of 3 using the point (1, 1) as the point of
CaHeK987 [17]

Answer: D'(-14,1);\ E'(4,7);\ F'(4,1)

Step-by-step explanation:

Since the center of dilation is not at the origin, we can use the following formula in order to find the coordinates of the vertices of the triangle D'E'F':

D_{O,k}(x,y)=(k(x-a)+a, k(y-b)+b)

Where "O" is the center of dilation at (a,b) and "k" is the scale factor.

In this case you can identify that:

(a,b)=(1,1)\\k=3

Therefore, susbtituting values into the formula shown above, you get that the coordinates ot the resulting triangle D'E'F, are the following:

Vertex D' → (3(-4-1)+1,\ 3(1-1)+1)=(-14,1)

Vertex E' → (3(2-1)+1,\ 3(3-1)+1)=(4,7)

Vertex F' → (3(2-1)+1,\ 3(1-1)+1)=(4,1)

6 0
3 years ago
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