If an adult blinks 450 times in 30 minutes, then he will blink 900 times in 60 minutes.
A 12-year old blinks 150 times in 15 minutes, so he will blink (150 x 4) in 60 minutes, which comes out to: 600.
so 900-600
An adult blinks 300 times more in 60 minutes than a 12-year old.
A community group bought 30 tickets to an amusement park at a total cost of $810. They bought x student tickets for $25 each and y adult tickets for $30 each.
***
let x=number of student tickets bought
30-x=number of adult tickets bought
..
25x+30(30-x)=810
25x+900-30x=810
5x=90
x=18
30-x=12
number of student tickets bought=18
number of adult tickets bought=12
Hope this helps!
Answer: Is this a fun fact??? If it is then this is not related to math at all
Step-by-step explanation:
Answer:
Hope it helps....!!!!!
Step-by-step explanation:
AB = c = 38
BC = a = 29
AC = b
Angle ABC = 63 degrees
Solving for AC "b":
Cosine rule: c^2 = a^2 * b^2 -2ab * cos C
38^2 = 29^2 * b^2 - (2* 29) * b * (cos 38)
1444 = 841 * b^2 - 58 * b * 0.955
(1444 + 58)/0.955 = b^2 * b
1572.77486911 = b^3
11.62935 = b
11.63 = b (rounded to two decimal places)
Now solving for angle A:
Sine rule: a/sinA = b/sinB
29/sinA = 11.63/sin(63)
sinA/29 = sin(63)/11.63
sin A = (sin(63)/11.63) * 29
sin A = 0.41731
A = sin^-1 (0.41731)
A = 24 degrees 39 minutes 53 seconds
Now solving for angle C:
Sine rule: c/sinC = b/sinB
38/sinC = 11.63/sin(63)
sinC/38 = sin(63)/11.63
sin C = (sin(63)/11.63) * 38
sin C = 0.54682
C = sin^-1 (0.54682)
C = 33 degrees 8 minutes 56 seconds
