Question

I have to find the angle measurements of a interior triangle a is 4x b is 7x-2 and c is 5x-10

Answer 1

Answer:

$m\angle a=48^o\\m\angle b=82^o\\m\angle c=50^o$

Step-by-step explanation:

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

$m\angle a+m\angle b+m\angle c=180^o$

substitute the given values

$4x^o+(7x-2)^o+(5x-10)^o=180^o$

solve for x

$(16x-12)^o=180^o$

$16x=180+12\\16x=192\\x=12$

Find the angle measurements

$m\angle a=4(12)=48^o$

$m\angle b=7(12)-2=82^o$

$m\angle c=5(12)-10)=50^o$