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777dan777 [17]
3 years ago
7

Write two division expression s that have the same vaule as 36.8 ÷ 2.3

Mathematics
1 answer:
Triss [41]3 years ago
7 0
<h3><u>Write two division expression s that have the same vaule as 36.8 ÷ 2.3 </u></h3>

32 \div 2 = 16\\\\48 \div 3 = 16

<em><u>Solution:</u></em>

Given that,

We hve to find the two division expression s that have the same vaule as 36.8 ÷ 2.3

From given,

36.8 \div 2.3 = 16

So, we have to find two division expressions that has a value of 16

<em><u>First division expression</u></em>

We know that 32 divided by 2 gives 16

Thus, we can write as,

32 \div 2 = 16

<em><u>Second Expression:</u></em>

We know that 48 divided by 3 gives 16

Thus, we can write as,

48 \div 3 = 16

Thus the two expressions are found

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Answer:

<h2>         X-intercept: (2, 0) </h2><h2>         Y-intercept: (0, 6) </h2>

Step-by-step explanation:

X-intercept means y-coordinate of 0:

6x +2×0 = 12

6x = 12

  x = 2         ← x-coordinate

Y-intercept means x-coordinate of 0:

6×0 + 2y = 12

2y = 12

  y = 6         ← y-coordinate

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3 years ago
Can someone help me.
Sauron [17]

Answer:

The answer to your question is: 20°

Step-by-step explanation:

Data

m∠XZY = 40

m∠XZB = 20

Process

1.- Find the measure of ∠ XAB

   ∠XAB = 40°   because AB ║ YZ

2.- Find the measure of ∠ZAB

     ∠ZAB + ∠XAB = 180

    ∠ZAB = 180 - ∠XAB

    ∠ZAB = 180 - 40

    ∠ZAB = 140°

3.- Find the measure of ∠ABZ

    The sum of the internal angles in a triangle equals 180°

     ∠AZB + ∠ZAB + ∠ABZ = 180

     20° + 140° + ∠ABZ = 180

     ∠ABZ = 180 - 20 - 140

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7 0
3 years ago
Molly buys 12 rolls of wallpaper for £111.00.<br> How much is 1 roll of wallpaper?
alex41 [277]

Answer: £9.25


111.00/12=9.25

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3 years ago
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A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

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Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

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