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3 years ago

How long will it take to travel 200km traveling 10 m/s

Mathematics

1 answer:

jolli1 [7]3 years ago

6 0

Answer:

time = distance / speed

time = 200/10

= 20

Step-by-step explanation:

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Find the domain of the graphed function.

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For every point on the curve, imagine drawing a vertical line until that vertical line reaches the x axis.

Doing this will essentially shade the x axis number line from x = -4 to x = 2

The graph shows points in which the x coordinate is as small as -4 or as large as 2, or anything in between

Domain: $-4 \le x \le 2$
Answer: Choice B

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Write the equation of the function whose graph is shown. y = (x + )2 +

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Quadratic form is given in the form
$y= ax^{2}+bx+c$ , where a, b, and c are constants

We substitute the value (8, 12) and (5,3) in turn

$12= a(8)^{2}+b(8)+c$
$12=64a+8b+c$ ... Equation 1

$3=a(5)^{2}+b(5)+c$
$3=25a+5b+c$ ... Equation 2

Equation 1 - Equation 2 gives
$39a+3b=9$ , we call this Equation 3

We also know that (5, 3) is the turning point of the curve, where the value of $x$ is given by $x=- \frac{b}{2a}$
Substitute $x=5$
$5=- \frac{b}{2a}$
$10a=-b$
$b=-10a$ ... Equation 4

Substitute Equation 4 into Equation 3
$39a+3b=9$
$39a+3(-10a)=9$
$39a-30a=9$
$9a=9$
$a=1$

Now we need to work out the value of $b$ and $c$

Substitute $a=1$ back into equation 4
$-10a=b$
$-10(1)=b$
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Substitute $a=1$ and $b=-10$ into either equation 1 or equation 2

$64a+8b+c=12$
$64(1)+8(-10)+c=12$
$64-80+c=12$
$c=12+80-64$
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Hence the equation of the quadratic curve is
$y= x^{2} 10x+28$

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Answer:

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Answer:

The intermediate step are;

1) Separate the constants from the terms in x² and x

2) Divide the equation by the coefficient of x²

3) Add the constants that makes the expression in x² and x a perfect square and factorize the expression

Step-by-step explanation:

The function given in the question is 6·x² + 48·x + 207 = 15

The intermediate steps in the to express the given function in the form (x + a)² = b are found as follows;

6·x² + 48·x + 207 = 15

We get

1) Subtract 207 from both sides gives 6·x² + 48·x = 15 - 207 = -192

6·x² + 48·x = -192

2) Dividing by 6 x² + 8·x = -32

3) Add the constant that completes the square to both sides

x² + 8·x + 16 = -32 +16 = -16

x² + 8·x + 16 = -16

4) Factorize (x + 4)² = -16

5) Compare (x + 4)² = -16 which is in the form (x + a)² = b

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