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3 years ago

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Answer to -5x-6x<8-8n-n

1 answer:

EastWind [94]3 years ago

6 0

First...
$Simplify\;-5x-6x \ \textgreater \ \mathrm{Add\:similar\:elements:}\:-5x-6x=-11x$

$Simplify\;8-8n-n \ \textgreater \ \mathrm{Add\:similar\:elements:}\:-8n-n=-9n$
$8 - 9n$

$-11x\ \textless \ 8-9n$

$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)} \ \textgreater \ 11x\ \textgreater \ -8+9n$

$\mathrm{Divide\:both\:sides\:by\:}11 \ \textgreater \ \frac{11x}{11}\ \textgreater \ -\frac{8}{11}+\frac{9n}{11}$

$Simplify \ \textgreater \ x\ \textgreater \ \frac{-8+9n}{11}$

Hope this helps!

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IgorC [24]

Answer/Step-by-step explanation:

Given, $b(x) = (\frac{6}{7})^{x}$

The table for the function are:

When x = -2

$b(-2) = (\frac{6}{7})^{-2}$

$b(-2) = \frac{1}{(\frac{6}{7})^{2}}$

$b(-2) = \frac{1}{(\frac{36}{49})}$

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$b(-2) = \frac{49}{36}$

When x = -1

$b(-1) = (\frac{6}{7})^{-1}$

$b(-1) = \frac{1}{(\frac{6}{7})}$

$b(-1) = 1*\frac{7}{6}$

$b(-2) = \frac{7}{6}$

When x = 0

$b(0) = (\frac{6}{7})^{0}$

$b(0) = \frac{6^0}{7^0}$

$b(0) = \frac{1}{1}$

$b(0) = 1$

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$b(1) = (\frac{6}{7})^{1}$

$b(1) = \frac{6}{7}$

When x = 2

$b(2) = (\frac{6}{7})^{2}$

$b(2) = \frac{6^2}{7^2}$

$b(2) = \frac{36}{49}$

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