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dolphi86 [110]
3 years ago
9

Factor: 16g^2-26gh-35h^2

Mathematics
1 answer:
Sever21 [200]3 years ago
6 0

Answer:

The factored form would be (8g + 7h)(2g - 5h)

Step-by-step explanation:

In order to find this, we need to use factors of 16g^2 in the front of the parenthesis. We also need to use factors of -35h^2 in the second side. Now we try these in the parenthesis and FOIL until we get an appropriate middle term.

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Light travels at 186,000 miles per second. Light takes about 11⁄3 seconds to travel from the earth to the moon. Calculate the di
san4es73 [151]

Answer:

682,000 miles

Step-by-step explanation:

Using the ratio of 186,000 miles per second:

\frac{miles}{second}=\frac{186,000}{1}

we can set up a proportion (equivalent ratios) to find the distance, in miles, from the earth to the moon

\frac{186,000}{1}=\frac{x}{\frac{11}{3}} where 'x' is the number of miles between the earth and the moon

Cross-multiply:  x = 186,000*\frac{11}{3}

Solve for x = 682,000 miles

7 0
3 years ago
Show all work to factor x^4 − 17x^2 + 16 completely.
Dmitrij [34]

Answer:

x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

Step-by-step explanation:

At first, let us find the first two factors of x^{4}-17x^{2} +16

∵ The sign of the last term is positive

∴ The middle signs of the two factors are the same

∵ The sign of the middle term is negative

∴ The middle signs of the two factors are negative

∵ x^{4} = x² × x² ⇒ first terms of the two factors

∵ 16 = -1 × -16 ⇒ second terms of the two factors

∵ x²(-1) + x²(-16) = -x² + -16x² = -17x² ⇒ the value of the middle term

∴ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

Now let us factorize each factor

→ The factors of the binomial a² - b² (difference of two squares) are

   (a - b) and (a + b)

∵ x² - 1 is the difference of two squares

∴ Its factors are (x - 1) and (x + 1)

∵ x² - 16 is the difference of two squares

∴ Its factors are (x - 4) and (x + 4)

∵ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of (x² - 1) and (x² - 16)

∵ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

∴ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of x^{4}-17x^{2} +16

∴  x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

8 0
3 years ago
A square has an area of 36 cm. how long is one of its sides?
Leokris [45]
The correct answer would be 6.

To figure this out, you take the square root of 36 since area of a square is side x side.
8 0
3 years ago
How do you solve for #23
Bingel [31]
5 is you answer because absolute value is the distance on a number line from 0
8 0
3 years ago
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
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