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kirill115 [55]
3 years ago
14

It is possible to obtain a ""quick-and-dirty"" estimate of the mean of a normal distribution from the 50th percentile value on a

normal probability plot. Provide an argument why this is so. It is also possible to obtain an estimate of the standard deviation of a normal distribution by subtracting the 84th percentile value from the 50th percentile value. Provide an argument explaining why this is so.
Mathematics
1 answer:
frozen [14]3 years ago
8 0

Answer:

Step-by-step explanation:

It is possible to obtain a ""quick-and-dirty"" estimate of the mean of a normal distribution from the 50th percentile value on a normal probability plot, because normal distribution curve is symmetrical about its mean with 50% on either side of the mean. Also it is unimodal, with mean = median = mode. Because of symmetrical shape, and other special properties we can obtain estimate of mean as the 50th percentile of any normal distribution.

Also in normal distribution 34% lie between mean and 1 std deviation on right side/left side

This gives 84th percentile is got by taking the z value on right side of mean.

When we subtract 84th percentile value from the 50th percentile value we really get -1 times std deviation.  Hence to get std deviation actual value, without negative sign, we subtract (50-34) = 16th percentile from mean.

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Feliz [49]

Answer:

Answer:

Step-by-step explanation:

1st expression:4a(a-b)

2nd expression:9a(a-b)

So L.C.M=a(a-b)4×9

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8 0
3 years ago
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allochka39001 [22]

Answer:

Part 1) solution {(-5,8),(3,0)} ----> y+12=x^{2}+x and x+y=3

Part 2) No solutions ----> y-15=x^{2}+4x and x-y=1

Part 3) solution [(-2,5),(3,-5)] ---> y+5=x^{2}-3x and 2x+y=1

Part 4) No solutions ---> y-6=x^{2}-3x and x+2y=2

Part 5) solution [(2,3),(8,9)] --->y-17=x^{2}-9x and -x+y=1

Part 6) solution [(-2,3),(7,-6)] --->y-15=-x^{2}+4x and x+y=1

Step-by-step explanation:

Part 1) we have

y+12=x^{2}+x ----> equation A

x+y=3 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-5,8) and (3,0)  

see the attached figure N 1

Part 2) we have

y-15=x^{2}+4x ----> equation A

x-y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs  

see the attached figure N 2

Part 3) we have

y+5=x^{2}-3x ----> equation A

2x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,5) and (3,-5)  

see the attached figure N 3

Part 4) we have

y-6=x^{2}-3x ----> equation A

x+2y=2 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs    

see the attached figure N 4

Part 5) we have

y-17=x^{2}-9x ----> equation A

-x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (2,3) and (8,9)  

see the attached figure N 5

Part 6) we have

y-15=-x^{2}+4x ----> equation A

x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,3) and (7,-6)  

see the attached figure N 6

5 0
3 years ago
Plz help fast.Aka please don't waste my points.Show your Work
Andrej [43]
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3 years ago
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BlackZzzverrR [31]

Answer:

132 cm^2

Step-by-step explanation:

Find all areas and add together.

A = L x W

tA = (L x W)/2

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Hi 

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Hoped I Helped 
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3 years ago
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