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3 years ago

Write a function rule for the table. x f(x) (–3, 1) (–2, 2) (–1, 3) (0, 4)

Mathematics

2 answers:

inn [45]3 years ago

7 0

The answer is (1,1) a liner function

Mila [183]3 years ago

3 0

Hope this helps but the function rule for this table is f(x)=x+4

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Choose Yes or No to tell if the fraction 3 5 will make each equation true. 7 20 + □ = 19 20 Choose... □ + 3 10 = 3 15 Choose...

OleMash [197]

Answer:

True ; false ; False ; true

Step-by-step explanation:

Equation 1:

7 20 + □ = 19 20

19 / 20 - 7/20

(19 - 7) / 20

12/ 20 = 3/5

Equation 2:

□ + 3 10 = 3 15

3/5 + 3/10

(6 + 3) / 10 = 9/10

Equation 3:

1 2 + 2 3 = □

1/ 2 + 2/3

(3 + 4) / 6

7 / 6

Equation 4:

1 10 + 1 2 = □

1/10 + 1/2

(1 + 5) / 10

6 / 10 = 3/5

4 0

3 years ago

1 point

DedPeter [7]

Answer:

160000m³

Step-by-step explanation:

Volume of a rectangular prism= A x h

V= l x b x h

V= 80x 50 x 40

V= 160000m³

5 0

3 years ago

If 13sin a = -5 and tan a > 0, use a diagram to evaluate: 3cos a.

Crank

Answer:

naguguluhan ako ahh wait lang solve ko

4 0

3 years ago

6i =(x + i)(y + i)+1

erastova [34]

Answer:znmdzfhnnnnnncv

Step-by-step explanation: bvcxjcdjhdfnjdg

4 0

2 years ago

Pn=1/3pn-1 and p4=108 , then p6= ? please show steps

Natali5045456 [20]

$p_n=\dfrac13p_{n-1}$
$\implies p_n=\dfrac13\left(\dfrac13p_{n-2}\right)=\dfrac1{3^2}p_{n-2}$
$\implies p_n=\dfrac13\left(\dfrac13p_{n-3}\right)=\dfrac1{3^3}p_{n-3}$

and so on, up to

$p_n=\dfrac1{3^{n-4}}p_4=\dfrac{108}{3^{n-4}}$

which means

$p_6=\dfrac{108}{3^{6-4}}=\dfrac{108}9=12$

6 0

3 years ago