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Kisachek [45]
4 years ago
14

Which determinants can be used to solve for x and y in the system of linear equations below?

Mathematics
2 answers:
Elena L [17]4 years ago
4 0

<u>Answer:</u>

The correct answer option is A. |A|=\begin{vmatrix}-3 &2 \\ 4&-15 \end{vmatrix}\\\\\\|A_{x}|=\begin{vmatrix}-9 &2 \\ -25 &-15 \end{vmatrix}\\\\\\|A_{y}|=\begin{vmatrix}-3 &-9 \\ 4 &-25\end{vmatrix}.

<u>Step-by-step explanation:</u>

We are given the following system of linear equations:

-3x+2y=-9

4x-15y=-25

We can create a matrix  AX = b where A is a 2×2 matrix created by the coefficients of x and y and b is a 2×1 matrix formed by the term after equality.

So the correct answer option is:

|A|=\begin{vmatrix}-3 &2 \\ 4&-15 \end{vmatrix}\\\\\\|A_{x}|=\begin{vmatrix}-9 &2 \\ -25 &-15 \end{vmatrix}\\\\\\|A_{y}|=\begin{vmatrix}-3 &-9 \\ 4 &-25\end{vmatrix}

zlopas [31]4 years ago
3 0

Answer:

The right answer is the first answer

Step-by-step explanation:

Look to the attached file

Download docx
You might be interested in
If AA and BB are two disjoint events with P(A)=0.15P(A)=0.15 and P(B)=0.75P(B)=0.75, find the following probabilities:
zubka84 [21]

Answer:

a 0

b) 0.9

c) 0.85

d) 0.25

e) 0.1

f) 0.0375

Step-by-step explanation:

a)

As A and B are two disjoints events, then P(A and B) is

P(A and B)=0

b)

As A and B are two disjoints events, then P(A or B) is

P(A or B)=P(A)+P(B)

P(A or B)=0.15+0.75=0.9

c)

P(not A)=1-P(A)

P(not A)=1-0.15=0.85

d)

P(not B)=1-P(B)

P(not B)=1-0.75=0.25

e)

P(not (A or B))=1-P(A or B)

P(not (A or B))=1-0.9=0.1

f)

P(A and (not B))=P(A)*P(not B)

P(A and (not B))=0.15*0.25=0.0375

5 0
3 years ago
What is 1997 from 2014????????????
katen-ka-za [31]
What? That doesn't make sence! Any way if you mean 1997 to 2014 how many years.
3 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP:
dmitriy555 [2]

Answer:

39.34 juniors and 30.1 seniors

8 0
3 years ago
Read 2 more answers
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

\mu = 62.5 in

\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

   (in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
3 years ago
What is the area of this composite figure, in square centimeters?<br> 176<br> 209<br> 242<br> 264
e-lub [12.9K]

Answer:

209

Step-by-step explanation:

We can divide the figure into 2 parts to make this easier.

11x16=176 so the square is 176 square cm.

(11x6)/2 = 66/2 = 33 so the triangle is 33 square cm.

176+33 = 209 sq cm.

3 0
3 years ago
Read 2 more answers
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