That's not a linear system, but you have an awesome school system for giving you this problem.
Multiply by 6xy to clear the fractions.
That's a second degree equation, also known as a conic. That one happens to be a hyperbola.
Let's clear the fractions from the second equation, multiplying out common denominator xy:
We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.
Substituting,
We have to rule out x=0 because it's in the denominator.
Answer: (44/19, 33/20)
Answer:
3 times
Explanation:
We know that:
small diameter = 2 * 10^-2 in
large diameter = 6 * 10^-2 in
We want to know how many times larger is the thin diameter compared to the large one.
We will do this as follows:
large diameter = k * small diameter
where k is the number of times that we want to find
6 * 10^-2 = k * 2 * 10^-2
k = (6 * 10^-2) / (2 * 10^-2)
k = 3
This means that the large diameter is 3 times the small one.
Hope this helps :)
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
Answer:
Step-by-step explanation:
Ok, so we start by setting the integral up. The integral we need to solve is:
so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:
U=5+x
du=dx
x=U-5
so when substituting the integral will look like this:
now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:
so we must define p, q, p' and q':
p=ln U
q'=U-5
and now we plug these into the formula:
Which simplifies to:
Which solves to:
so we can substitute U back, so we get:
and now we can simplify:
notice how all the constants were combined into one big constant C.
