$\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15$

3 0

2 years ago

1x+11y=55 substitution

STatiana [176]

Answer:

y = -1/11 + 5

Step-by-step explanation:

1x + 11y = 55

-1x -1x

11y = -1x + 55

/11 /11

y = -1/11 + 5

Hope this helps!

4 0

2 years ago

I NEED HELP ASAP PLS WILL MARK BRINLIEST!!!

d1i1m1o1n [39]

Step-by-step explanation:

wait, I will look my lecture last year

5 0

3 years ago

Quick please no links or anything just the straight up answer answer both please

zlopas [31]

For 27) D
For 28) A
Hope that helps!

8 0

2 years ago

Read 2 more answers

Show the tens fact you used. Write the difference. 16-9= 10-___=_____

Show the tens fact you used. Write the difference. 16-9= 10-_=___