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poizon [28]
3 years ago
9

X^2+6x=-22 witch of the following is a solution

Mathematics
1 answer:
zysi [14]3 years ago
4 0

Answer:

x1=-3+i*sqrt(13)

x2=-3-i*sqrt(13)

Step-by-step explanation:

x^2 +6x=-22

x^2 +6x+22=0 (Quadratic equation)

a=1, b=6, c=22

x1=(-b+sqrt(b^2-4ac)) /2a

x1=(-6+sqrt(6^2 -4*1*22))/2*1

x1=(-6+sqrt(36-88))/2

x1=(-6+sqrt(-52))/2

x1=(-6+sqrt(52i^2))/2...... i^2=-1

x1=(-6+sqrt (4*13i^2))/2

x1=(-6+2i*sqrt(13))/2

x1=-3+i*sqrt(13)

x2=(-b-sqrt(b^2-4ac)) /2a

x2=-3-i*sqrt(13)

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Quadrilateral ABCD is a rectangle. If AE = 36 and CE = 2x - 4, find x.<br> B<br> E<br> А.<br> D
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The value of the x is 20 if the quadrilateral ABCD is a rectangle and  AE = 36 and CE = 2x - 4 because the diagonal of the rectangle bisect each other.

<h3>What is the area of the rectangle?</h3>

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The formula for finding the area of a rectangle is given by:

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Learn more about the rectangle here:

brainly.com/question/15019502

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