1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vedmedyk [2.9K]
3 years ago
6

The food calorie, equal to 4186 J, is a measure of how much energy is released when food is metabolized by the body. A certain b

rand of fruit-and-cereal bar contains 150 food calories per bar. Part A If a 68.0 kg hiker eats one of these bars, how high a mountain must he climb to "work off" the calories, assuming that all the food energy goes only into increasing gravitational potential energy?
Physics
1 answer:
rewona [7]3 years ago
5 0

Answer:

The hiker has to climb 941.26 to ''work off'' the calories.

Explanation:

Let's first find out how much energy the hiker gets from 150 food calories.

This is:

Energy = 150 * 4186

Energy = 627.9 kJ

To burn all of this off, we set it equal to the gravitational potential energy, and then solve for the height.

This is:

Gravitational Potential Energy (G.P.E) = 629700

G.P.E = mass * gravity * height

Thus,

mass * gravity * height = 629700

68 * 9.81 * height = 629700

height = 941.26 meters

You might be interested in
A wire carries a steady current of 2.60 A. A straight section of the wire is 0.750 m long and lies along the x axis within a uni
ad-work [718]

Answer:

The magnetic force on the section of wire is -2.925\hat{j}\ N.

Explanation:

Given that,

Current I = 2.60\hat{i}\ A

Length = 0.750 m

Magnetic field B = 1.50\hat{k}\ T

We need to calculate the magnetic force on the section of wire

Using formula of magnetic force

\vec{F}=l\vec{I}\times\vec{B}

\vec{F}=0.750\times2.60\hat{i}\times1.50\hat{k}

Since, \hat{i}\times\hat{k}=-\hat{j}

\vec{F}=-2.925\hat{j}\ N

Hence, The magnetic force on the section of wire is -2.925\hat{j}\ N.

7 0
3 years ago
A copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o
REY [17]

Answer:

550000000N/m

Explanation:

Given that a copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends of the wire, the wire stretches by 5.0×10−3 of its original length.

Original length L = 0.005L

the strain = extension/ original length

the strain = 0.005L / L

the strain = 0.005

Young modulus = stress / strain

11 × 10^10 = stress / 0.005

Cross multiply

Stress = 11 × 10^10 × 0.005

Stress = 550 000000 N/m

Therefore, the tensile stress on the wire is 550000000 N/m.

7 0
3 years ago
If Object C and Object D both have the same momentum, which statement is true? Question 11 options: They both have the same velo
Leya [2.2K]

Answer:

The product of mass times velocity for both objects is the same.

Explanation:

They both have the same velocity. False

They both have the same mass. False: Because two objects of different masses can have the same momentum. The least massive of the two objects will have the greatest kinetic energy.

The product of mass times velocity for both objects is the same. True: Same momentum means that the large mass must have a small velocity; therefore, their product is equal to the small mass times a large velocity.

Mass and velocity is the same for both. False: Based on what was stated for the second option.

7 0
3 years ago
Consider the flow of an incompressible Newtonian fluid between two parallel plates that are 4 mm apart. If the upper plate moves
marin [14]

Answer:

Net flow rate = 0.00035 m³/s

Explanation:

The speed of plate 1, U₁ = 5 m/s

The speed of plate 2, U₂ = 1.5 m/s

The two plates are moving in different directions, the net speed will be gotten by taking the difference of the average of the two plates

The average speed due to the movement of plate 1 = U₁/2 = 5/2 = 2.5 m/s

The average speed due to the movement of plate 2 = U₂/2 = 1.5/2

      = 0.75 m/s

The net average speed of the fluid= U₁/2 - U₂/2

The net average speed of the fluid = 2.5 - 0.75 = 1.75 m/s

Net flow rate = Net average speed * Area of the plate

Width of the plate, v = 5 cm = 0.05 m

Distance between the plates = 4 mm = 0.004 m

Area = 0.05 * 0.004

Area = 0.0002 m²

Net flow rate = 1.75 * 0.0002

Net flow rate = 0.00035 m³/s

8 0
3 years ago
A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge?
lara [203]
The magnitude of the source is 2.2 C
6 0
3 years ago
Read 2 more answers
Other questions:
  • There are several different models that represent compounds. One type of model is shown.
    9·2 answers
  • A wave of sound proceeds through the auditory canal to the inner ear where receptor neurons on the basilar membrane are stimulat
    6·1 answer
  • How do I find magnitude of acceleration?
    7·1 answer
  • PLS HELP! If you are given force and distance, you can determine power if you know (2 points)
    9·2 answers
  • A flat, 101 turn current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 5.61×10−4 m2, and the an
    10·1 answer
  • What are two force componentes of projectile motion
    8·1 answer
  • What is a oxidation number
    6·2 answers
  • What is the best inference for the speed of the car after 3 seconds
    8·1 answer
  • URGENT HELP PLS
    8·1 answer
  • Suppose you apply a force of 75 N to a 25-kg object. What will the acceleration of the object b? (Remember a=F/m)
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!