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Liula [17]
2 years ago
7

How do I find magnitude of acceleration?

Physics
1 answer:
Leno4ka [110]2 years ago
6 0
Divide the change in speed by the time for the change.
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The moon is 384,403 km from the earth how many quarters laid end to end it would take to reach the moon if a quarter has a diame
diamong [38]

Answer:

Distance from the moon= dm= 384,403km

A quarter diameter= dq= 2.3 cm= 0.000023km

No of quarters= 16,713,173, 913

To convert cm into km divide cm by 100 and then by 1000

as

1m= 100cm

1km= 1000m

Therefore

2.3/100= 0.023 m

And

0.023/1000= 0.000023 km

Dividing the distance from the moon by the diameter of the quarter laid end to end would give the number of the quarters needed.

No. of quarters= Distance from the moon/ Diameter of the quarter

                             = 384,403km/0.000023 km

                             =       16,713,173,913.043

Rounding  16,713,173,913.043 gives 16,713,173,913 quarters

Explanation:

Brainliest, please!

7 0
1 year ago
A 8 kilogram cat is resting on top of a bookshelf that is 2 meters high. What is the cat’s gravitational potential energy relati
slava [35]

-ZERO-   No 17.6 pound Earth-bound cat is going to be able to jump to the top of a 6 feet 7 inch bookshelf unassisted!  Someone should call the SPCA on the writer of this textbook question ;-)

Assuming that this overweight cat is content being placed in such a lofty position, your professor probably wants the answer of <u>156.8 Joules</u>

Mass x  Acceleration of Gravity (on Earth) x elevation = Potential Energy

8 Kg x 9.8 m/s2  x 2 m  = 156.8 J


3 0
3 years ago
Someone help plzz :))
Luden [163]

How did you take a picture?
3 0
3 years ago
Read 2 more answers
On Friday, September 28, 2018, Palu, Indonesia, on the island of Sulawesi, experienced an earthquake that generated a tsunami. F
Naily [24]

Answer: Proximity to active volcanoes

Explanation:

When volcanoes erupt, they can generate tsunamis in the following ways:

-Parts of the volcano (some of them may be underwater) could collapse, generating a big displacement of water and resulting in a tsunami.

-The magma chamber could also collapse as it empties, also generating water displacement.

-If the volcanoes are near to the shore, debris resulting from the eruption could hit the water at fast speeds, producing big waves and eventually a tsunami.

In this case, the proximity of Palu city to active volcanoes, especially ones that are so close to the shore, increases the risk of a tsunami.

7 0
3 years ago
A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the
Rudiy27

The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C

R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)={26\times 10^{-6}\;\mathrm{C}}

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

E=\dfrac{Q}{4\pi\epsilon_0 r^2}

Substitute numerical values:

E&=\dfrac{24\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.6)}\\ &={6.49\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.

As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).

Learn more about Gaussian sphere here:

brainly.com/question/2004529

#SPJ4

6 0
1 year ago
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