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Zolol [24]
3 years ago
11

A copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o

f the wire, the wire stretches by 5.0×10−3 of its original length. What is the tensile stress on the wire? Young's modulus for copper is 11×1010Pa.
Physics
1 answer:
REY [17]3 years ago
7 0

Answer:

550000000N/m

Explanation:

Given that a copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends of the wire, the wire stretches by 5.0×10−3 of its original length.

Original length L = 0.005L

the strain = extension/ original length

the strain = 0.005L / L

the strain = 0.005

Young modulus = stress / strain

11 × 10^10 = stress / 0.005

Cross multiply

Stress = 11 × 10^10 × 0.005

Stress = 550 000000 N/m

Therefore, the tensile stress on the wire is 550000000 N/m.

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Moving a magnet around a coil of wire, or moving a coil of wire around a magnet, pushes the electrons in the wire and creates an electrical current. Electricity generators essentially convert kinetic energy (the energy of motion) into electrical energy. which are called magnetic fields.

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Explanation:

(c) I assume we're looking for mA.

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T = mAa

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8 0
3 years ago
How could you increase the force advantage of a lever?Select one:a. Make the effort length longer.b. Make the effort length shor
11Alexandr11 [23.1K]

The ideal mechanical advantage of a lever (IMA) is given by:

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Answer:

a. Make the effort length longer.

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11 months ago
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For the wave of light you generated in the Part B, calculate the amount of energy in 1.0 mol of photons with that same frequency
Angelina_Jolie [31]

Answer:

2.7 J

Explanation:

The energy of one photon is given by

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So the total energy of N_A photons contained in 1.0 mol is

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