Answer: The concentrations of at equilibrium are 0.112 M, 0.112 M and 0.260 M
Explanation:
Moles of = 1.45 mole
Moles of = 1.45 mole
Volume of solution = 6.00 L
Initial concentration of =
Initial concentration of =
The given balanced equilibrium reaction is,
Initial conc. 0 M 0.242 M 0.242 M
At eqm. conc. (2x) M (0.242-x) M (0.242-x) M
The expression for equilibrium constant for this reaction will be,
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
x = 0.130
Thus, the concentrations of at equilibrium are :
Concentration of = (0.242-x) M = (0.242-0.130) M = 0.112 M
Concentration of = (0.242-x) M = (0.242-0.130) M = 0.112 M
Concentration of = 2x M = = 0.260 M