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marin [14]
4 years ago
7

5(2^(2x+7)) How do you solve this equation??

Mathematics
1 answer:
Liono4ka [1.6K]4 years ago
3 0
Simplifying
0x + 7 + 5x = 2x + 30 + 40

Anything times zero is zero.
0x + 7 + 5x = 2x + 30 + 40

Combine like terms: 0 + 7 = 7
7 + 5x = 2x + 30 + 40

Reorder the terms:
7 + 5x = 30 + 40 + 2x

Combine like terms: 30 + 40 = 70
7 + 5x = 70 + 2x

Solving
7 + 5x = 70 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
7 + 5x + -2x = 70 + 2x + -2x

Combine like terms: 5x + -2x = 3x
7 + 3x = 70 + 2x + -2x

Combine like terms: 2x + -2x = 0
7 + 3x = 70 + 0
7 + 3x = 70

Add '-7' to each side of the equation.
7 + -7 + 3x = 70 + -7

Combine like terms: 7 + -7 = 0
0 + 3x = 70 + -7
3x = 70 + -7

Combine like terms: 70 + -7 = 63
3x = 63

Divide each side by '3'.
x = 21

Simplifying
x = 21
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Why do some quadratic graphs move left or right and others do not? Is there a correlation between this and them moving up and do
Vikentia [17]

Answer:

(x + 3)^2 is left 3 because it becames 0 at -3

(x - 3)^2 is right 3  because it becames 0 at 3

x^2 +3 is up 3  because your just adding 3 units up

x^2 - 3 is down 3 because your just subtracting 3 units down

Step-by-step explanation:

8 0
3 years ago
(Will give Brainliest)
jek_recluse [69]
I believe it’s 8^3 I’m sorry if it’s wrong!!!!
5 0
4 years ago
Read 2 more answers
Plz help, I don't understand this.
Oksanka [162]

Answer:

see explanation

Step-by-step explanation:

consecutive even integers have a difference of 2 between them

for example 2, 4, 6 are 3 consecutive even integers

In general if we let the first integer be k then the next 2 integers are

k + 2 and k + 4

the sum of these equals 4 times the first integer, that is 4k, hence

k + k + 2 + k + 4 = 4k

3k + 6 = 4k ( subtract 3k from both sides )

6 = k

the 3 consecutive integers are

k = 6

k + 2 = 6 + 2 = 8

k + 4 = 6 + 4 = 10

that is 6, 8 and 10

note that sum = 6 + 8 + 10 = 24

and 4 × 6 = 24

confirming the sum of the 3 integers equals 4 times the first integer




7 0
3 years ago
What is the range of the function y = -x2 + 1?
meriva
<span><span>y = 2 + 2sec(2x) The upper part of the range will be when the secant has the smallest positive value up to infinity. The smallest positive value of the secant is 1 So the minimum of the upper part of the range of y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4 So the upper part of the range is [4, ) The lower part of the range will be from negative infinity up to when the secant has the largest negative value. The largest negative value of the secant is -1 So the maximum of the lower part of the range of y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0 So the lower part of the range is (, 0]. Therefore the range is (, 0] U [4, ) </span>
</span>
3 0
3 years ago
Graph the function f(x)=−13x+1.
pogonyaev

Graph each points:

f(x) = -13x + 1

when x = 0, y = 1

f(0) = -13(0) + 1

f(0) = 0 + 1

f(0) = 1

when x = 1, y = -14

f(1) = -13(1) + 1

f(1) = -13 + 1

f(1) = -14

when x = 2, y = -25

f(2) = -13(2) + 1

f(2) = -26 + 1

f(2) = -25

etc.

Graph each point and connect them.

7 0
4 years ago
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