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3 years ago

22. Which is the interquartile range for

Mathematics

1 answer:

Readme [11.4K]3 years ago

7 0

Answer:

Step-by-step explanation:

Variability is a measures of the interquartile range of a given set of data. The greater the interquartile range, the more the variability.

The interquartile range (IQR) = Third quartile (Q3) - First Quartile (Q1)

IQR for City A = 70 - 40 = 30

IQR for City B = 80 - 40 = 40.

City B has a greater IQR value, therefore, it has the greater variability in temperature.

The interquartile range for the city with greater variability is 40.

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3 years ago

Rahul deposited a sum of Rs.32500 in the bank for 2 years, compounded half yearly at 12% per annum. Find the compound interest h

trasher [3.6K]

Answer:

The compound interest earn for amount deposited in bank is Rs 8,530.275

Step-by-step explanation:

Given as :

The principal deposited in account = p =Rs 32,500

The rate of interest = r= 12% compounded half yearly

The time period = t = 2 years

let The Amount after 2 years = Rs A

Let The compound interest earn = C.I

Now, From Compound Interest method

Amount = Principal × $(1+\dfrac{\textrm rate}{2\times 100})^{\extrm time\times 2}$

or, A = p × $(1+\dfrac{\textrm r}{2\times 100})^{\extrm t\times 2}$

Or, A = Rs 32,500 × $(1+\dfrac{\textrm 12}{2\times 100})^{\extrm 2\times 2}$

Or, A = Rs 32,500 × $(1.06)^{4}$

Or, A = Rs 32,500 × 1.26247

∴ A = Rs 41030.275

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Now, Again

Compound Interest = Amount - Principal

C.I = A - p

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∴ C.I = Rs 8,530.275

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8 0

3 years ago

I put a picture —PLEASE HELP

Karo-lina-s [1.5K]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Base of a cube is a square, and in the given figure it's stated that the measure of each side is " x " ft

Therefore it's Area is equal to : -

$side \times side$

$x \times x$

${x}^{2}$

Now, since it's Area is given as 1/4 ft², let's equate the Areas to find the measure of each side ~

that is ~

${x}^{2} = \dfrac{1}{4}$

$x = \sqrt{ \dfrac{1}{2} \times \dfrac{1}{2} }$

$x = \dfrac{1}{2} \: \: feet$

It's time to find the volume of cube that is ~

$(side) {}^{3}$

So, let's plug the value of side length (1/2 ft)

Volume is equal to ~

${ \bigg(\dfrac{1}{2} \bigg) }^{3}$

$\dfrac{1}{8} \: \: ft {}^{3}$

Hence, the required 1/8 or 0.125 ft³

I hope it helped ~

$\mathrm{✌TeeNForeveR✌}$

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