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How many grams of C6H6O3 will react with 97.0grams of O2?<br><br> C6H6O3+3O2 ===> 6CO+3H2O

likoan [24]

Answer:

127.3 g

Explanation:

Data Given

mass of O₂= 97 g

mass of C₆H₆O₃ = ?

Reaction Given:

C₆H₆O₃ + 3O₂ --------> 6CO + 3H₂O

Solution:

First find the mass of C₆H₆O₃ from the reaction that it combine with how many grams of oxygen (O₂).

Look at the balanced reaction

C₆H₆O₃ + 3O₂ --------> 6CO + 3H₂O

1 mol 3 mol

So 1 mole of C₆H₆O₃ combine with 3 moles of O₂

Now

convert the moles into mass for which we have to know molar mass of C₆H₆O₃ and O₂

Molar mass of C₆H₆O₃

Molar mass of C₆H₆O₃ = 6(12) + 6(1) +3(16) = 72 + 6 + 48

Molar mass of C₆H₆O₃ = 126 g/mol

mass of C₆H₆O₃

mass in grams = no. of moles x molar mass

mass of C₆H₆O₃ = 1 mol x 126 g/mol

mass of C₆H₆O₃ = 126 g

Molar mass of O₂ = 2(16)

Molar mass of O₂= 32 g/mol

mass of O₂

mass in grams = no. of moles x molar mass

mass of O₂ = 3 mol x 32 g/mol

mass of O₂ = 96 g

So,

96 g of O₂ combine with 126 g of C₆H₆O₃ then how many grams of C₆H₆O₃ will combine with 97.0grams of O2

Apply unity Formula

96 g of O₂ ≅ 126 g of C₆H₆O₃

97 g of O₂ ≅ X g of C₆H₆O₃

By cross multiplication

X g of O₂ = 126 g x 97 g / 96 g

X g of O₂ = 127.3 g

127.3 g of C₆H₆O₃ will combine with 97 g of O₂

So

mass of C₆H₆O = 127.3 g

7 0

3 years ago

What is the molarity of 40ml of NaOH if it takes 25ml of 0.5 molar HCl to neutralize it?

Oksanka [162]

Answer:

Molarity of 40 ml of NaoH is 0.3125 mL

Explanation:

As we know

Molarity of acid * volume of acid = molarity of base * volume of base

Substituting the given values, we get

$0.5 * 25 = X* 40 \\X = \frac{0.5*25}{40} \\X = 0.3125$

Molarity of 40 ml of NaoH is 0.3125 mL

6 0

3 years ago

For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give a

GREYUIT [131]

The element that was oxidized is carbon, as it’s oxidation state increased (electrons were lost) from +2 (in the reactants) to +4 (in the products). The element that was reduced is nitrogen, as it gained electrons and went from a +2 oxidation state (reactants) to a 0 oxidation state (products). Since the carbon was oxidized and it’s electrons were used to reduce the nitrogen, carbon is the reducing agent.

7 0

4 years ago

Air containing 0.06% carbon dioxide is pumped into a room whose volume is 12,000 ft3. The air is pumped in at a rate of 3,000 ft

castortr0y [4]

Answer:

$A(t)=1.8+34.2*e^{-t}$