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3 years ago

Please do 1-5! giving 5 stars and thanks if right!

Chemistry

1 answer:

Burka [1]3 years ago

6 0

Answer:

1. 100 centimeters

2. 1 gram

3. 1000 meters

4. 10 millimeters

5. 1000 grams

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: Citric acid, H3C6H5O7, is a triprotic acid. Consider a buffer system comprising H2C6H5O7 - and HC6H5O7 2- ions. What is the ne

olchik [2.2K]

Answer:

The Net reaction is

$H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction$
$H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH$
$HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH$

Explanation:

From the Question we are told that the buffers are

$H_2C_6H_5O_7^ -$ and $HC_6H_5O_7 ^{ 2-}$

When NaOH is added the Net ionic reaction would be

$H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction$
$H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH$
$HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH$

8 0

3 years ago

Read 2 more answers

Realice las siguientes conversiones: a) 72°F a °C, b) 213.8°C a °F, c)180°C a K, d) 315K a °F, e) 1750°F a K, f) 0K a °F.

bonufazy [111]

Answer:

a) 72 °F= 22.22 °C

b) 213.8 °C= 416.84°F

c) 180 °C= 453.15 °K

d) 315 °K= 107.33 °F

e) 1750 °F= 1227.594 °K

f) 0 °K= -459.67 °F

Explanation:

Para realizar el intercambio de unidades debes tener en cuenta las siguientes conversiones:

Fahrenheit a Celsius: $C=\frac{F-32}{1.8}$

Celsius a Fahrenheit: °F= °C*1.8 + 32
Celsius a Kelvin: °K= °C + 273.15
Kelvin a Fahrenheit: F= (K -273.15)*1.8 + 32
Fahrenheit a Kelvin: $K=\frac{F-32}{1.8} + 273.15$

Entonces se obtiene:

a) 72 °F= $\frac{72-32}{1.8}$ =22.22 °C

b) 213.8 °C= 213.8*1.8 + 32= 416.84°F

c) 180 °C= 180°C + 273.15= 453.15 °K

d) 315 °K= (315 -273.15)*1.8 + 32= 107.33 °F

e) 1750 °F= $\frac{1750-32}{1.8} + 273.15$ = 1227.594 °K

f) 0 °K= (0 -273.15)*1.8 + 32= -459.67 °F

7 0

3 years ago

the s and p sublevels of an atom of an element in period 3 are filled with electrons. Which orbitals are filled in this atom?

7nadin3 [17]

<span>s sublevel = s orbital p sublevel= p orbitals the level tells you which orbitals exactly,
so level 3,
sub level p = 3p orbitals </span>

7 0

3 years ago

Read 2 more answers

The density of lead is 11.3 g/cm. What is the mass of a cube of lead with 10.0 cm on each edge? Show work please.

tresset_1 [31]

Mass of the lead cube :

$\boxed{ \boxed{11.3 \: \: kg}}$

4 0

3 years ago

What's the lowest to greatest order for scales of universe?

elena55 [62]

Answer:

universe

Explanation:

tell me if im wrong

4 0

3 years ago