Answer:
1st image, 17.79 g Mg(NO3)2
2nd image 1.47 mol NH3
3rd image Molar Mass Al(OH)3 = 78 g/mol
Explanation:
1st image
Molar Mass Mg(NO3)2 = 148. 31 g/mol
0,12 mol Mg(NO3)2 x (148, 31 g Mg(NO3)2 / 1 mol Mg(NO3)2) = 17.79 gMg(NO3)2
2nd image
Molar Mass NH3 = 17g/mol
25 g NH3 x ( 1 mol NH3/ 17 g NH3) = 1.47 mol NH3
3rd image
Molar Mass Al(OH)3 = 1 Al *(27) + 3 O * (16) + 3 H * (1) = 78 g/mol
