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3 years ago

Please answer these questions fast! Im on a time crunch right now

Chemistry

1 answer:

REY [17]3 years ago

4 0

Answer:

1st image, 17.79 g Mg(NO3)2

2nd image 1.47 mol NH3

3rd image Molar Mass Al(OH)3 = 78 g/mol

Explanation:

1st image

Molar Mass Mg(NO3)2 = 148. 31 g/mol

0,12 mol Mg(NO3)2 x (148, 31 g Mg(NO3)2 / 1 mol Mg(NO3)2) = 17.79 gMg(NO3)2

2nd image

Molar Mass NH3 = 17g/mol

25 g NH3 x ( 1 mol NH3/ 17 g NH3) = 1.47 mol NH3

3rd image

Molar Mass Al(OH)3 = 1 Al *(27) + 3 O * (16) + 3 H * (1) = 78 g/mol

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Consider the Gibbs energies at 25 ∘C.

zysi [14]

Answer:

A)ΔGrxn∘=55.7kJ/mol

B)Ksp=1.75×10^−10

C)ΔGrxn∘=70.0kJ/mol

D)Ksp=5.45×10^−13

Explanation:

ΔGrxn∘=ΔGf,products∘−ΔGf,reactants∘

To calculate for the

Ksp

of the dissolution reaction can be claculated

ΔGrxn∘=−RTlnKsp

where R is the proportionality constant equal to 8.3145 J/molK.

ΔGrxn∘=[ΔGf,Ag(aq)+∘+ΔGf,Cl(aq)−∘]−ΔGf,

AgCl(s)⇌Ag(aq)++Cl(aq)−

ΔG∘rxn=[77.1kJ/mol+(−131.2kJ/mol)]−(−109.8kJ/mol)

ΔGrxn∘=55.7kJ/mol

b) Calculate the solubility-product constant of AgCI.

ΔGrxn∘=−RTlnKsp

55.7kJ/mol=−(8.3145×10−3J/molK)(298.15K)InKsp

Ksp=1.75×10^−10

c) Calculate

To calculate ΔG°rxn

for the dissolution of AgBr(s).

ΔGrxn∘=[ΔGf,Ag(aq)+∘+ΔGf,Br(aq)−∘]−ΔGf,

ΔGrxn∘=[77.1kJ/mol+(−104.0kJ/mol)]−(−96.90kj/mol

ΔGrxn∘=70.0kJ/mol

d)To Calculate the solubility-product constant of AgBr.

ΔGrxn∘=−RTlnKsp

70.0kJ/mol=−(8.3145×10−3J/molK)(298.15K)lnKsp

70.0kJ/mol=−(8.3145×10−3J/molK)(298.15K

Ksp=5.45×10^−13

8 0

3 years ago

Which is and element A) Salad B) Sugar C) Water D) Potassium

Semenov [28]

Answer:

the only element above is potassium

3 0

4 years ago

Why are dark matter and dark energy described as "dark"? A. Because they emit blackbody radiation. B. Because they absorb light.

VMariaS [17]

Answer:

D. Because we cannot easily detect them.

Explanation:

Dark matter are called dark because using existing astronomical instruments we are blinded to them. Dark matter and dark energy are difficult to detect and properly observe. As we know that the whole universe is made up of matter, some of the matter do not interact with the electromagnetic radiations which makes undetectable.

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4 years ago

A bowling ball (mass = 7.2 kg, radius = 0.10 m) and a billiard

evablogger [386]

Answer:

Maximum gravitational Force: $F_{gmax} = 1,026*10^{-08} N$

Explanation:

The maximum gravitational force is achieved when the center of gravity are the closer they can be. For the spheres the center of gravity is at the center of it, so the closer this two centers of gravity can be is:

bowling ball radius + billiard ball radius = 0,128 m

The general equation for the magnitude of gravitational force is:

$F_{gmax} = G \frac{M*m}{r_{min}^{2} }$

Solving for:

$G = 6,67*10^{-11} \frac{Nm^{2}}{kg^{2}}$

$M = 7,2 kg$

$m = 0,35 kg$

$r_{min} = 0,128 m$

The result is:

$F_{gmax} = 1,026*10^{-08} N$

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4 years ago

Find the number of moles of water that can be formed if you have 210 mol of hydrogen gas and 100 mol of oxygen gas.

liraira [26]

200 moles The balanced equation for creating water from hydrogen and oxygen gas is 2H2 + O2 => 2H2O So for every mole of oxygen gas, you need two moles of hydrogen. So looking that the amount of oxygen and hydrogen you have, it's obvious that oxygen is the limiting reactant since 100 moles of oxygen will consume 200 moles of hydrogen. While 210 moles of hydrogen requires 105 moles of oxygen. Now for each mole of oxygen gas you use, you create 2 moles of water. So 100 mol * 2 = 200 mol So you can create 200 moles of water from the given amounts of reactants.

6 0

4 years ago