water balloons are tossed from the roof of a building, all with the same speed but with different launch angles. Which one has t
1 answer:
Answer:
90°/-90°
Explanation:
assume we are measuring launch angles with respect to horizontal surface
assume +y direction to be positive
when object is launched with launch angle <90° but >0°
it has 2 components for velocity v
in horizontal direction
in vertical direction
the <u>component remains unchanged throughout the travel</u> as there is no force acting on it to change it (air resistance is ignored)
this component is decreased till 0, as acceleration due to gravity is acting on it and<u> starts to increase in downward direction</u>.
when ball reaches the same height of the building while going down, this vertical component of ball is equal same as but in opposite direction
so now vertical velocity = -
this <u>component keeps on increasing until it hits the ground</u> as the gravity accelerates it to the ground
the horizontal component is unchanged throughout
So to have maximum speed when the ball reaches the ground,the vertical velocity component must be maximum at launch,so it will <u>just be accelerated until it hits the ground.</u>
⇒ In this case,the maximum vertical component can be v or -v
⇒=v or
= -v
⇒ horizontal component is 0
this means that ball is thrown directly up at 90° or directly down at 90° with respect to horizontal.
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Answer:
A) 1 N
B) 50 N
Explanation:
Let us consider that the string does not deform.
To solve this problem lets consider the whole system as two parts. In the initial case, the first part will be de 100N being exterted to the whole system and in the second the 100 blocks system.
In this case we can imagine as the whole system being pulled by 100 N, and therefore its acceleration will be:
a = 100 N /(100 m)
where m stantds for the mass of one block
Now, the whole system and its individual parts must move with the same acceleration otherwise the string would stretch.
Now lets consider the first part of the system as the first block, and the second part as the other 99 blocks.
The Tension of the string pulling the 99 blocks must be so that it exterts the enough force to move that 99blocks-system at an acceleration a, since that sub-system has a mass of 99m
T1 = 99 m * a = (99 m) * (100 N/ 100 m) = 99 N
Now lets consider an intermidiate sub-system, where the first part is made of n blocks and the second susbsystem is made of (100 -n) blocks
Following the same logic, the tension of the corresponding string must be the acceleration of the whole systems times the mass of the second subsystem:
Tn = (100 -n)m * ( 100 N / 100 m ) = (100 -n) N
a)
Therefore the tension in the string connecting block 100 to block 99 must be
<u>T99 = 1 N</u>
<u />
b)
And
<u>T50 = 50 N</u>
