As close as I can read it, it appears to be
1/12 gram/second
(0.08333... gm/sec)
Answer:
16 male students, 11 female students
-17.555m/s
first I found the time it took for jacks stone to reach the bottom, using the formula vf = vi + at, vf and vi are final and initial velocities.
then i found the velocity at 6.6m using vf^2 = vi^2 + 2ad
and I found the time it took to get to 6.6m, so that I knew how long Jill waited to throw her stone, I used the formula d = t(vi+vf)/2, then i done total time - the time she waited, to get the time it took for there stones to hit the ground at the same time.
then to find the initial velocity of her throw I used the formula d = vit + (at^2)/2
This is a statement not a question .
Answer:
16.03m(2dp)
Explanation:
Ep=m x g x h
1100=7.0x 9.8( gravitational field strength) x h
Height= 1100/7.0 x 9.8
=16.03498542
= 16.03m (2dp)
