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Lady bird [3.3K]
3 years ago
13

If AB = 62, find the value of x. Show your work

Mathematics
1 answer:
tangare [24]3 years ago
6 0
3x+16+2x-4=62
5x+12=62
5x=62-12
5x=50
x=10
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andreyandreev [35.5K]

Answer:

i believe >

Step-by-step explanation:

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Lara has 75 magazines She sells them for $3 each this situation is modeled by y=3x whereby is the amount of money she makes and
drek231 [11]
Hello!

Since she can not make negative money and the maximum amount of money she can make is 225 so the domain is

0 \leq x \leq 225

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4 0
3 years ago
In a certain clothing store, 3 shirts and 5 ties cost $60, and 2 shirts and 3 ties cost $39. What is the cost of each shirt?
Dovator [93]
Let shirts be x and ties be y
3x+5y=$60    Equation 1 (Equation 1 will be denoted by *)
2x+3y=$39    Equation 2 (Equation 2 will be denoted by !)
*x2  6x + 10y = $120
!x3  6x + 9y = $117
*-!  y = 120-117 =3

Ties are $3 each
Substitute this value back into one of the original 2 equations:
3x+5y=$60
3x+(5x3) = 60
3x+15=60
3x=45
x=15

Shirts are $15


6 0
3 years ago
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Following calculus questions. Thanks so much
Brrunno [24]

The vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be:

B. x = 0

C. x = +-2π

<h3>How to illustrate the information?</h3>

It should be noted that the function that's given from the information illustrated is given as:

y = 3 for (x/2) - 4

It should be noted that there is no phase shift and the period is 2π.

It should be noted that the vertical asymptote will be x = 3πn where no is represented as the integer at n = 0, 1, and -1.

Therefore, the vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be x = 0 and x = +2π.

Learn more about calculus on:

brainly.com/question/24430269

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7 0
2 years ago
(1 point) An insurance company offers its policyholders a number of different premium payment options. For a randomly selected p
Olegator [25]

Answer:

a)

X    |  1        3      5       7

f(X) | 0.4   0.2   0.2    0.2

b) P(4

Step-by-step explanation:

For this case we have defined the cumulative distribution function like this:

F(X) = 0, x

F(X) = 0.4, 1 \leq x

F(X) = 0.6, 3 \leq x

F(X) = 0.8, 5 \leq x

F(X) = 1, x \geq 7

And we know that the general definition for the distribution function is given by:

F(x) = P(X \leq x) = \sum_{i\leq k} f(i)

Where f represent the density function.

Part a

For this case we need to find the density function, so we can find the values for the density for each value of X = 1,2,3,4,5,6,7,... since X is a discrete random variable.

f(1) = P(X=1) = P(X \leq 1) - P(X=0) = F(1) -F(0) = 0.4-0=0.4

f(2) = P(X=2) = P(X \leq 2) - P(X=0)- P(X=1) = F(2) -F(1) = 0.4-0.4=0

f(3) = P(X=3) = P(X \leq 3) - P(X=0)- P(X=1) -P(X=2) = F(3) -F(2) = 0.6-0.4=0.2

f(4) = P(X=4) = P(X \leq 4) - P(X=0)- P(X=1) -P(X=2)-P(X=3) = F(4) -F(3) = 0.6-0.6=0

f(5) = P(X=5) = P(X \leq 5) - P(X=0)- P(X=1) -P(X=2)-P(X=3)-P(X=4) = F(5) -F(4) = 0.8-0.6=0.2

f(6) = P(X=6) = P(X \leq 6) - P(X=0)- P(X=1) -P(X=2)-P(X=3)-P(X=4)-P(X=5) = F(6) -F(5) = 0.8-0.8=0

f(7) = P(X=7) = P(X \leq 7) - P(X=0)- P(X=1) -P(X=2)-P(X=3)-P(X=4)-P(X=5)-P(X=6) = F(7) -F(6) = 1-0.8=0.2

And for any value higher than 7 we have that:

x_i \in [8,9,10,...]

f(x_i) = F(X_i) -F(X_i -1) = 1-1=0

So then we have our density function defined like this:

X    |  1        3      5       7

f(X) | 0.4   0.2   0.2    0.2

Part b

For this case we want to find this probability P(4

And since the random variable is discrete we can write this like that:

P(4

5 0
3 years ago
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