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Flura [38]
3 years ago
13

HELP PICTURE IS SHOWN

Mathematics
1 answer:
Ronch [10]3 years ago
6 0
Letter B is the answer
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In circle K shown below, points B, C, D, and E lie on the circle with secants HBD and HCE drawn. Prove:
Alexxx [7]

Answer:

By exterior angle theorem, we have;

∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC

∴ ∠H + ∠HEB = ∠H + ∠HDC

By addition property of equality, we have

∠HEB = ∠HDC

∠H = ∠H by reflexive property

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Therefore, by cross multiplication, we have;

HE × DC = EB × HD

Therefore, by commutative property of multiplication, we have;

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Step-by-step explanation:

3 0
3 years ago
Solve the formula for the indicated variable.<br> T(r+s)=rs, for r<br> (Simplify your answer.)
yaroslaw [1]

Answer:

R = \frac{-TS}{(T-S)}

Step-by-step explanation:

First, distribute all terms

T(R+S) =RS\\TR + TS =RS

Get all terms with R onto the same side

TR + TS = RS\\TR - RS = -TS

Factor out the R

R(T-S)=-TS

Divide by (T-S) to isolate R

R = \frac{-TS}{(T-S)}

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