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3 years ago

Find the length of the missing side. It’s a written response

Mathematics

2 answers:

andre [41]3 years ago

8 0

Using Pythagorean’s theorem, the side length is sqrt(89)

vekshin13 years ago

4 0

Answer:

the missing side is $\sqrt{89}$

Step-by-step explanation:

We use Pythagoras theorem

$8^{2} +5^{2} =x^{2} \\64 + 25 = x^{2} \\89=x^{2} \\\sqrt{89} =x$

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Help- ASAP please (25 points)

Alina [70]

Answer:

(t^2 -4) (t^2 +4)

(t-2)(t+2)(t^2+4)

Step-by-step explanation:

t^4 - 16

We can write this as the difference of squares

We know the dfference of squares is

(a^2 - b^2) = (a-b) (a+b)

( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4)

We can write t^2 -4 as the difference of squares

t^2 -4 = t^2 -2^2 = (t-2)(t+2)

Replacing this in

( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4) = (t-2)(t+2)(t^2+4)

8 0

4 years ago

Read 2 more answers

The area of a rectangle is greater than 60 ft. The width of the rectangle is 2x - 3 ft and the

34kurt

Answer:

Inequaliy: 2x-3(12)>60

X>48

Step-by-step explanation:

Since area of a rectangle is W(L)=A

The inequality given right here including length And width and area Plugged in would be

2x-3(12)>60. (It’s >60 because the area stated in the problem said to be greater then 60 so we put a Greater then sign)

Combine like terms and solve

2x-36>60

Add 36 on both sides

2x>96

Divide 2 on both sides to isolate variable

x>48

Check:

2(50)-36>60 ( I used 50 because it’s greater then 48 and it’s a easy number to work with for just a check)

solve:

100-36>60

64>60✔️

7 0

3 years ago

Need assistance please thanks.

Nitella [24]

I guess the answer is 66

5 0

3 years ago

los trabajadores de una mina se encuentran a 20 metros bajo tierra .Si excavan 3 metros desde alli suben otros 8 metros para cog

Yakvenalex [24]

Step-by-step explanation:

la carretilla estaba a unos 15 metros de altura

8 0

3 years ago

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, should the signs in the binom

gtnhenbr [62]

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, the signs in the binomials should be both positive

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the true statement?</h3>

The form of the polynomial is given as:

ax2 + bx + c

Where a, b, and c are positive real numbers.

Since a, b, and c are positive real numbers. then the form of the expansion would be:

ax2 + bx + c = (dx + e)(fx + g)

<h3>Example to verify the claim</h3>

Take for instance, we have the following quadratic equation

x^2 + 6x + 8

Expand the equation

x^2 + 6x + 8 = x^2 + 4x + 2x + 8

Factorize the equation

x^2 + 6x + 8 = (x + 2)(x + 4)

Hence, the signs in the binomials should be both positive