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Ipatiy [6.2K]
3 years ago
11

You're a manager in a company that produces rocket ships. Machine A and Machine B both produce cockpits and propulsion systems.

Machine A and Machine B produce cockpits at the same rate, and they produce propulsion systems at the same rate. Machine A ran for 26 hours and produced 4 cockpits and 6 propulsion systems. Machine B ran for 56 hours and produced 8 cockpits and 12 propulsion systems. We use a system of linear equations in two variables. Can we solve for a unique amount of time that it takes each machine to produce a cockpit and to produce a propulsion system?
Mathematics
2 answers:
GalinKa [24]3 years ago
7 0

Answer:

No you cannot.

Step-by-step explanation:

Let c be the amount of time it takes each machine to make 1 cockpit, and p be the amount of time it takes each machine to make 1 propulsion system.

For Machine A, we have 4 cockpits; this would take 4c time.  We also have 6 propulsion systems; this would take 6p time.  Together it takes 26 hours; this would give us

4c+6p=26.

For Machine B, we have 8 cockpits; this would take 8c time.  We also have 12 propulsion systems; this would take 12p time.  Together it takes 56 hours; this would give us

8c+12p=56

This gives us the system

\left \{ {{4c+6p=26} \atop {8c+12p=56}} \right.

To solve this, we want the coefficients of one of the variables to be the same.  To make the coefficients of c the same, we can multiply the top equation by 2:

\left \{ {{2(4c+6p=26)} \atop {8c+12p=56}} \right. \\\\\left \{ {{8c+12p=52} \atop {8c+12p=56}} \right.

To cancel c, we will subtract the second equation from the first one.  However, this also cancels p:

\left \{ {{8c+12p=52} \atop {-(8c+12p=56)}} \right. \\\\0+0=-4\\0=-4

We get a statement that is not true; thus the system has no solution, and we cannot solve for a unique amount of time.

EleoNora [17]3 years ago
6 0

Answer:

Step-by-step explanation:

Given :

Machine A ran for 26 hours and produced 4 cockpits and 6 propulsion systems.

Machine B ran for 56 hours and produced 8 cockpits and 12 propulsion systems.

To Find :  Can we solve for a unique amount of time that it takes each machine to produce a cockpit and to produce a propulsion system?

Solution :

Let x be the time taken to produce 1 cockpits

So, time taken to produce 4 cockpits = 4x

So, time taken to produce 8 cockpits = 8x

Let y be the time taken to produce 1 Propulsion

So. time taken to produce 6 propulsion = 6y

So. time taken to produce 12 propulsion = 12y

Now we are given that Machine A ran for 26 hours and produced 4 cockpits and 6 propulsion systems.

⇒4x+6y =26  --a

We are also given that Machine B ran for 56 hours and produced 8 cockpits and 12 propulsion systems.

⇒8x+12y =56  --b

Solving equation a and b by substitution method

Substitute the value of x from equation in b

⇒8(\frac{26-6y}{4}) +12y =56

⇒52-12y+12y =56

⇒52 =56

We get a statement that is not true; thus the system has no solution, and we cannot solve for a unique amount of time.

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