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ohaa [14]
3 years ago
6

H(x)=10-3/2x, find h(-6)

Mathematics
2 answers:
Elena-2011 [213]3 years ago
8 0

Answer:

\frac{41}{4}

Step-by-step explanation:

To evaluate h(- 6), substitute x = - 6 into h(x)

h(- 6) = 10 - \frac{3}{2(-6)} = 10 - \frac{3}{-12} = 10 + \frac{3}{12}

h(- 6) = 10 + \frac{1}{4} = 10 \frac{1}{4} = \frac{41}{4}



Andrei [34K]3 years ago
8 0

Answer:

h(x)=10-3/(2x), h(-6)=10+3/12=10.25

h(x)=10-(3/2)x, h(-6)=10+(3/2)×6=19


Step-by-step explanation:

3/2x is ambiguous, because traditional algebra says 3/2x = 3/(2x) but ever since FORTRAN came out in c.1958, programming languages say 3/2x = (3/2)x. WELL IN 1958 COMPUTERS DIDN'T HAVE LOWER CASE, AND XY WAS XY, NOT X*Y, SO IT WAS 3/2*X=(3/2)*X AND NOT 3/(2*X). ALSO FORTRAN IGNORED ALL BLANK SPACES SO X Y WAS ALSO XY NOT X*Y.



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