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3 years ago

If it is 9:38 what time would it be a half and hour later

Mathematics

1 answer:

snow_tiger [21]3 years ago

4 0

Answer:

If it was 9:38 it would be 10:08

Step-by-step explanation:

Adding 30 to 38 would be 68. And since an hour is only 60 minuets long you would change the hour to 10 and add the 8 minuets.

Hope this helped! :))

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Check whether the relation R on the set S = {1, 2, 3} is an equivalent

kozerog [31]

Answer:

$R$ isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let $S$ denote a set of elements. $S \times S$ would denote the set of all ordered pairs of elements of $S\!$ .

For example, with $S = \lbrace 1,\, 2,\, 3 \rbrace$ , $(3,\, 2)$ and $(2,\, 3)$ are both members of $S \times S$ . However, $(3,\, 2) \ne (2,\, 3)$ because the pairs are ordered.

A relation $R$ on $S\!$ is a subset of $S \times S$ . For any two elements $a,\, b \in S$ , $a \sim b$ if and only if the ordered pair $(a,\, b)$ is in $R\!$ .

A relation $R$ on set $S$ is an equivalence relation if it satisfies the following:

Reflexivity: for any $a \in S$ , the relation $R$ needs to ensure that $a \sim a$ (that is: $(a,\, a) \in R$ .)

Symmetry: for any $a,\, b \in S$ , $a \sim b$ if and only if $b \sim a$ . In other words, either both $(a,\, b)$ and $(b,\, a)$ are in $R$ , or neither is in $R\!$ .

Transitivity: for any $a,\, b,\, c \in S$ , if $a \sim b$ and $b \sim c$ , then $a \sim c$ . In other words, if $(a,\, b)$ and $(b,\, c)$ are both in $R$ , then $(a,\, c)$ also needs to be in $R\!$ .

The relation $R$ (on $S = \lbrace 1,\, 2,\, 3 \rbrace$ ) in this question is indeed reflexive. $(1,\, 1)$ , $(2,\, 2)$ , and $(3,\, 3)$ (one pair for each element of $S$ ) are all elements of $R\!$ .

$R$ isn't symmetric. $(2,\, 3) \in R$ but $(3,\, 2) \not \in R$ (the pairs in $\! R$ are all ordered.) In other words, $3$ isn't equivalent to $2$ under $R\!$ even though $2 \sim 3$ .

Neither is $R$ transitive. $(3,\, 1) \in R$ and $(1,\, 2) \in R$ . However, $(3,\, 2) \not \in R$ . In other words, under relation $R\!$ , $3 \sim 1$ and $1 \sim 2$ does not imply $3 \sim 2$ .

3 0

3 years ago

Supply: p=q2+20q, Demand: p=-4q2+10q-13,000 q=__

Tema [17]

I don’t know but I think it’s 13,207,156

6 0

3 years ago

Analyze the following situations that represent a relationship between x and y. Which situations can be modeled by the equation

SCORPION-xisa [38]

Answer:

I think it's A and D

Step-by-step explanation:

For option A, y would be the height or total growth, and x would be time or months and total height = 0.23 feet × 7.5 months

for option D, y would be the total amount of money spent and x would be the number of granola bars bought. total money spent = $0.23 × number of granola bars bought

Options B and C don't work because we don't know the initial values and an initial value would be represented in the equation.

In option E, 0.23 represents the total growth in 7 days, so it would be the total instead of the rate of change

8 0

3 years ago

Sin A 7 divided by 25

Brums [2.3K]

Answer:

Cos A = 24/25, Tan A = 7/25

Step-by-step explanation:

Given that Sin A = 7/25

Sin = Opp/hyp

Therefore using Pythagoras theorem, adjacent will be;

= √(25²-7²)

= √576

= 24

Thus;

Cos A = adjacent/hypotenuse

= 24/25

Cos A = 24/25

Tan A = opp/hypotenuse

= 7/25

Tan A = 7/25

4 0

3 years ago

Read 2 more answers

Hello if you're able to answer this question for me please do and provide work, Thank you

Harlamova29_29 [7]

The answer is c to your question

5 0

2 years ago