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2 years ago

Solve x^2-6x+5=0 by completing the square

Mathematics

1 answer:

Liula [17]2 years ago

6 0

Answer:

x=1 or x=5

Step-by-step explanation:

Let's solve your equation step-by-step.

x2−6x+5=0

Step 1: Factor left side of equation.

(x−1)(x−5)=0

Step 2: Set factors equal to 0.

x−1=0 or x−5=0

x=1 or x=5

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9 - 10x = 2x + 1 - 8x

Furkat [3]

Answer:

$x=2$

Step-by-step explanation:

$9 - 10x = 2x + 1 - 8x$

$9-10x=-6x+1$

Subtract 9 from both sides:

$9-10x-9=-6x+1-9$

$-10x=-6x-8$

Add 6x to both sides:

$-10x+6x=-6x-8+6x$

$-4x=-8$

Divide both sides by -4:

$\frac{-4x}{-4}=\frac{-8}{-4}$

$x=2$

8 0

3 years ago

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Simplify |3 - 11| - (15+ 3+2)2

Natalka [10]

Answer:

-26

Step-by-step explanation:

so, the absolute value of 3 and 11 together is 14.

14-(15+3+2)2

14-(20)2

14-40

-26

6 0

3 years ago

Please help with p and q maths geometry

baherus [9]

Step-by-step explanation:

in a very similar way, as the sum of all 4 angles in a triangle is always 180°, so is the sum of all angles in a quadrilateral (a polygon with 4 sides) 360°.

just look at rectangles at special representatives of such quadrilaterals.

now that we know this, we can simply say, the sum of all angles in our shape must be 360° :

(8x + 2) + (4x + 2) + (x - 2) + (5x -2) =

= 18x = 360

x = 20

A = 8×20 + 2 = 162°

B = 4×20 + 2 = 82°

C = 5×20 - 2 = 98°

D = 20 - 2 = 18°

a trapezium has the following properties (in the UK):

like other quadrilaterals, the sum of all the four angles of the trapezium is equal to 360°.

a trapezium has two parallel sides and two non-parallel sides.

the diagonals of a regular trapezium bisect each other.

in the USA for example the request for 2 parallel sides does not exist.

we have proven the point with the angle sum.

the other 2 are given by the diagram.

so, yes, it is a trapezium.

the sum of all interior angles of a polygon is

(n - 2) × 180°

n being the number of d sides.

we have here a regular pentagon (5 equal sides).

the size of the angle at any vertex is then

(5 - 2) × 180 / 5 = 3 × 180 / 5 = 3×36 = 108°.

so, theta = 108°.

alpha + beta = 108°

ABE is an isoceles triangle.

so, beta = angle 1

beta + angle 1 + theta = 180

2×beta + 108 = 180

2×beta = 72

beta = 36°

therefore,

alpha = 108 - beta = 108 - 36 = 72°

4 0

1 year ago

What are the values of x and y x=9/4 y=3/4 x=9/4 y=15/4 x=15/4 y=5/4 x=3/4 y=15/4

laiz [17]

The complete question in the attached figure

we know that

in the triangle BDC
cos alfa=3/y----------> equation 1
sin alfa=x/y----------> equation 2

in the triangle ABD
cos alfa=4/5--------> equation 3
sin alfa=3/5---------> equation 4

then

Equal equation 1 and 3
3/y=4/5---------> y/3=5/4----------> y=15/4

Equal equation 2 and 4
x/y=3/5-------> x=3*y/5------------> 3*15/(4*5)-----> x=9/4

the answer is
x=9/4 y=15/4

6 0

3 years ago

Find the value of each variable that makes the equation true.

Anastaziya [24]

What’s the equation?

3 0

2 years ago

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